Question

我需要有关如何正确执行此操作的帮助。我需要执行这个命令：

SELECT concat(branchname, -->, itemtype, '(, quantity, ')') from monitoring
order by itemtype;

语法在MySQL控制台中有效。但是，我在php上实现它有麻烦。我总是得到 “未定义的索引：branchname” “未定义的索引：itemtype” “未定义的索引：数量”

使用此代码：

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "dex_test";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

$sql = "SELECT concat(branchname,itemtype,quantity) from monitoring order by itemtype";
$result = mysqli_query($conn, $sql);

if (mysqli_num_rows($result) > 0) {
    // output data of each row
    while($row = mysqli_fetch_assoc($result)) {
        echo " " . $row["branchname"]. " " . $row["itemtype"]. " ".$row["quantity"]. "<br>";
    }
} else {
    echo "0 results";
}

mysqli_close($conn);

错误说它在这一行

echo " " . $row["branchname"]. " " . $row["itemtype"]. " ".$row["quantity"]. "<br>";

我很困惑，因为我基本上运行了相同的代码，可以让我看到表格中的itemtype：

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "dex_test";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

$sql = "SELECT itemtype FROM monitoring";
$result = mysqli_query($conn, $sql);

if (mysqli_num_rows($result) > 0) {
    // output data of each row
    while($row = mysqli_fetch_assoc($result)) {
        echo "itemtype: " . $row["itemtype"]. "<br>";
    }
} else {
    echo "0 results";
}

mysqli_close($conn);

帮助任何人？

Answer 1

只需定义连接列的别名即可。使用此 -

SELECT concat(branchname,itemtype,quantity) as branchname from monitoring order by itemtype

或者如果你想分开那么 -

SELECT branchname, itemtype, quantityfrom monitoring order by itemtype

Answer 2

您的查询似乎需要更新

"SELECT concat(branchname,itemtype,quantity) from monitoring order by itemtype";

应该是

"SELECT branchname,itemtype,quantity from monitoring order by itemtype";

我已经发布了这个答案，参考了你如何在while循环中调用你的字段

echo " " . $row["branchname"]. " " . $row["itemtype"]. " ".$row["quantity"]. "<br>";

如果你需要在一个字段中显示concat值而不是像

那样

$sql = "SELECT concat(branchname,' ',itemtype,' ',quantity) as branch from monitoring order by itemtype";
$result = mysqli_query($conn, $sql);

if (mysqli_num_rows($result) > 0) {
    // output data of each row
    while($row = mysqli_fetch_assoc($result)) {
        echo $row["branch"]."<br>";
    }
} else {
    echo "0 results";
}

使用PHP未定义变量

2 个答案: