Question

我想用regexp拆分一些字符串。但我无法得到我想的结果。我听说javascript不支持lookbehind。

val.split(/(?:([\.,?;\n])\s?)/gi)

["always on the go", "?", "if yes", ",", "slip-on this dress that comes with u-neck", ",", "long sleeves and loose fit", ".", "wear with slacks and beanie to finish the ensemble", ".", "", "
", "- u-neck", "
", "- long sleeves", "
", "- loose fit", "
", "- knee hemline", "
", "- plain print"]

我目前的结果是这样的

array[0] = "always on the go?"; array[1] = "if yes,"; ... ... ... array[n] = '↵' array[n] = '↵' array[n] = '- u-neck' ... ...

但我希望我的结果像这样

f1<-function(x) x/2+5
f2<-function(x) x/3-10

我该怎么做？

Answer 1

试试这个正则表达式，它会保留你的，？在句末。

@Path("myName/{var}")
public String getN(@PathParam("var") String s) {

    //my request has to lie here. It doesn't because it has one more resource.. I want to create sth like after /myname, Everything is to be on this method. How to do this?

    //like I wanted path value to be /is/foo



}

Answer 2

我能想到的唯一方法是编写自己的原型

replication level

并使用此

String.prototype.splitKeep = function(arr){
    if (!(arr instanceof Array)) throw('input array please');
    var value = this.toString();
    for (var i = 0; i < arr.length; i++){
        value = value.split(arr[i]).join(arr[i] + ":split:").trim();
    }
    value = value.split(":split:");
    //remove all newlines with characters
    for (var i = 0; i < value.length; i++){
        var item = value[i];
        if (item[item.length-1] === '\n' && item.length > 1){
            value[i] = item.substring(0, item.length-1);
        }
    }
    return value;
}

数组拆分时如何包含分隔符？

2 个答案: