我必须在编程设计某种类型的游戏时做一个最终项目，我决定使用石头剪刀。我开始编写程序而没有任何面向对象的编程风格，并意识到我必须改变它以获得项目的最大分数。但是，当我以OOP形式重写它时，它不会像没有OOP创建的那样工作。
这是我的OOP计划：
import javax.swing.*;
import java.awt.*;
import java.applet.*;
import java.util.Scanner;
import java.util.Arrays;
public class RockPaperScissorss extends Applet
{
protected String answer;
protected Image rock, paper, scissors;
protected boolean playAgain;
public void init()
{
answer = Expo.enterStringGUI("What is your first draw?");
rock = getImage(getDocumentBase(),"Rock.gif");
paper = getImage(getDocumentBase(),"Paper.gif");
scissors = getImage(getDocumentBase(),"Scissors.gif");
}
public void paint(Graphics g)
{
Output output = new Output();
playAgain = true;
while(playAgain == true)
{
output.displayYouAndComp(g);
output.getCompDraw();
output.displayPic1(g);
output.displayComp1(g);
output.whoWon();
output.printResult(g);
output.playAgain();
if(playAgain == true)
init();
}
}
}
class Initialize extends RockPaperScissorss
{
protected String again;
public void displayYouAndComp(Graphics g)
{
Expo.setFont(g,"Algerian",Font.BOLD,50);
Expo.drawString(g,"You",0,50);
Expo.drawString(g,"Computer",500,50);
}
public boolean playAgain()
{
again = Expo.enterStringGUI("Would you like to play again? (Y/N)");
if(again.equals("Y") || again.equals("y"))
playAgain = true;
else
playAgain = false;
return playAgain;
}
}
class Person extends Initialize
{
public void displayPic1(Graphics g)
{
if(answer.equals("rock"))
g.drawImage(rock,0,100,this);
else if(answer.equals("paper"))
g.drawImage(paper,0,100,this);
else
g.drawImage(scissors,0,100,this);
}
}
class Computer extends Person
{
protected int draw;
public void getCompDraw()
{
draw = Expo.random(0,2);
}
public void displayComp1(Graphics g)
{
if(draw == 1)
g.drawImage(rock,500,100,this);
else if(draw == 2)
g.drawImage(paper,500,100,this);
else
g.drawImage(scissors,500,100,this);
}
}
class Output extends Computer
{
protected boolean won;
protected int tieGame;
protected String result;
protected String newArray[];
public String[] whoWon()
{
newArray = new String[1];
String personAnswers[] = {answer};
int compAnswers[] = {draw};
for(int k = 0; k < 1; k++)
{
if(personAnswers[k].equals("rock"))
{
switch(compAnswers[k])
{
case 1: //rock
newArray[k] = "tie";
break;
case 2: //paper
newArray[k] = "loss";
break;
case 3: //scissors
newArray[k] = "win";
break;
}
}
else if(personAnswers[k].equals("paper"))
{
switch(compAnswers[k])
{
case 1:
newArray[k] = "win";
break;
case 2:
newArray[k] = "tie";
break;
case 3:
newArray[k] = "loss";
break;
}
}
else
{
switch(compAnswers[k]) //equals scissors
{
case 1:
newArray[k] = "loss";
break;
case 2:
newArray[k] = "win";
break;
case 3:
newArray[k] = "tie";
break;
}
}
}
return newArray;
}
public void printResult(Graphics g)
{
String[] result = newArray;
Expo.setFont(g,"Algerian",Font.BOLD,50);
int x = 200;
for(int k = 0; k < 1; k++)
{
if(result[k].equals("loss"))
Expo.drawString(g,"You lost!",700,x);
else if(result[k].equals("tie"))
Expo.drawString(g,"It's a tie!",700,x);
else
Expo.drawString(g,"You won!",700,x);
}
}
}
vs我的非OOP代码：
import javax.swing.*;
import java.awt.*;
import java.applet.*;
import java.util.Scanner;
import java.util.Arrays;
public class RockPaperScissorsss extends Applet
{
String answer1, answer2, answer3; //first draw, etc.
int firstDraw, secondDraw, thirdDraw;
int tieGame;
String[] newArray;
Image rock, paper, scissors;
boolean playAgain;
String again;
public void init()
{
answer1 = Expo.enterStringGUI("What is your first draw?");
rock = getImage(getDocumentBase(),"Rock.gif");
paper = getImage(getDocumentBase(),"Paper.gif");
scissors = getImage(getDocumentBase(),"Scissors.gif");
newArray = new String[1];
}
public void paint(Graphics g)
{
playAgain = true;
while(playAgain == true)
{
displayYouAndComp(g);
getCompDraw();
displayPic1(g);
displayComp1(g);
whoWon();
printResult(g);
playAgain();
if(playAgain == true)
init();
}
}
public boolean playAgain()
{
again = Expo.enterStringGUI("Would you like to play again? (Y/N)");
if(again.equals("Y") || again.equals("y"))
playAgain = true;
else
playAgain = false;
return playAgain;
}
public void displayYouAndComp(Graphics g)
{
Expo.setFont(g,"Algerian",Font.BOLD,50);
Expo.drawString(g,"You",0,50);
Expo.drawString(g,"Computer",500,50);
}
public void getCompDraw()
{
firstDraw = Expo.random(0,2);
secondDraw = Expo.random(0,2);
thirdDraw = Expo.random(0,2);
}
public void displayPic1(Graphics g)
{
if(answer1.equals("rock"))
g.drawImage(rock,0,100,this);
else if(answer1.equals("paper"))
g.drawImage(paper,0,100,this);
else
g.drawImage(scissors,0,100,this);
}
public void displayComp1(Graphics g)
{
if(firstDraw == 1)
g.drawImage(rock,500,100,this);
else if(firstDraw == 2)
g.drawImage(paper,500,100,this);
else
g.drawImage(scissors,500,100,this);
}
public String[] whoWon()
{
String personAnswers[] = {answer1};
int compAnswers[] = {firstDraw};
for(int k = 0; k < 1; k++)
{
if(personAnswers[k].equals("rock"))
{
switch(compAnswers[k])
{
case 1: //rock
newArray[k] = "tie";
break;
case 2: //paper
newArray[k] = "loss";
break;
case 3: //scissors
newArray[k] = "win";
break;
}
}
else if(personAnswers[k].equals("paper"))
{
switch(compAnswers[k])
{
case 1:
newArray[k] = "win";
break;
case 2:
newArray[k] = "tie";
break;
case 3:
newArray[k] = "loss";
break;
}
}
else
{
switch(compAnswers[k]) //equals scissors
{
case 1:
newArray[k] = "loss";
break;
case 2:
newArray[k] = "win";
break;
case 3:
newArray[k] = "tie";
break;
}
}
}
return newArray;
}
public void printResult(Graphics g)
{
String[] result = newArray;
Expo.setFont(g,"Algerian",Font.BOLD,50);
int x = 200;
for(int k = 0; k < 1; k++)
{
if(result[k].equals("loss"))
Expo.drawString(g,"You lost!",700,x);
else if(result[k].equals("tie"))
Expo.drawString(g,"It's a tie!",700,x);
else
Expo.drawString(g,"You won!",700,x);
x += 200;
}
}
}
如果代码难以理解，我会提前道歉。我做错了什么？
答案 0 :(得分：0)
我怀疑原因是因为＆＃34;输出＆＃34;延伸＆＃34; RockPaperScissorss＆＃34;当你执行＆＃34;输出输出=新输出（）;＆＃34;时，扩展＆＃34;小程序＆＃34;在paint（）中，您获得了一个不能访问＆＃34;显示＆＃34;的Applet的不同实例。你需要修复你的继承。
但是，我必须补充一点，你的程序无法实现OOP - 你只是展示了OOP的一个原则：继承（extends）。你缺少另外两个原则：多态（实现）和封装（在类和实现的其他部分共享受保护的布尔playAgain违反了这个原则）。所以，即使你让代码工作，我也会在你的项目上失败，除非你展示了所有的OOP原则。