Question

//story image to s3 bucket
    try {
        $s3->putObject([
                'Bucket' => $config['s3']['bucket'],
                'Key' => "uploads/{$name_of_uploaded_file}",
                'Body' => fopen($path_of_uploaded_file, 'rb'),
                'ACL' => 'public-read'
            ]);
        //remove the file
        unlink($path_of_uploaded_file);
    } catch(S3Exception $e){
        die("there was an error");
    }

    //retrieve image url
    $objects = $s3->getIterator('ListObjects', [
      'Bucket' => $config['s3']['bucket']
    ]);
    //put img url into variable so that it stores it into sql table
    $photoLink = $s3->getObjectUrl($config['s3']['bucket'], $objects['Key']);


if (is_uploaded_file($_FILES['uploaded_file']['size'])){
        //send items to pending database

            //note already connected to db

          //inserts in pending db
          $sql = "INSERT INTO pending (id,photo,title,description,name) VALUES ('', :photo, :title, :description, :name)";
          $stmt = $conn->prepare($sql); 
          $stmt->bindParam(':title', $title);
          $stmt->bindParam(':photo', $photoLink);
          $stmt->bindParam(':description', $story);
          $stmt->bindParam(':name', $first_name);
          $stmt->execute();       
    }else {
      header('Location:index.php');
    }

如何让php取出一个url，以便将ex：http://www.amazonaws/bucket/image.jpg存储到我的sql数据库列照片中？

现在我的网络应用程序给了我这个错误：不能在第127行使用Aws \ S3 \ Iterator \ ListObjectsIterator类型的对象作为数组

Answer 1

//retrieve image url
$objects = $s3->getIterator('ListObjects', [
  'Bucket' => $config['s3']['bucket']
]);

这不是你认为它正在做的事情。正如方法名称所示，这将使您获得迭代器，而不是内存数组。这个迭代器将覆盖存储桶中的每个项目，而不仅仅是您上传的文件。由于它是一个迭代器，当你尝试使用数组访问方法（$photoLink = $s3->getObjectUrl($config['s3']['bucket'], $objects['Key']);）时，它会爆炸。

你可能想要的是来自putObject（）的响应，你当前没有存储它。类似的东西：

try {
    $result = $s3->putObject([
<snip>

之后，您可以使用$result['ObjectURL']访问该网址。从putObject() is on Amazon's site返回的完整文档。

从亚马逊s3桶对象获取图像网址

1 个答案: