Question

我目前正在尝试编写将用户输入作为字符串的代码，然后在需要时将它们转换为整数。如果用户决定输入exit，则程序应继续调用函数。以下是我到目前为止的情况：

void printArray(string string_array[], int size){
    for (int i = 0; i < size; i++){
        cout << string_array[i];
    }

}
void a_func(){
    string string_array[10];
    string user_input;

    while (user_input != "exit"){
        cout << "Please enter a number between 0 - 100: ";
        cin >> user_input;
        if (stoi(user_input) < 0 || stoi(user_input) > 100){
            cout << "Error, please re-enter the number between 0 - 100: ";
            cin >> user_input;
        }
        else if (user_input == "exit"){
            printArray(string_array, 10);
        }
        int array_index = stoi(user_input) / 10;
        string_array[array_index] = "*";
}

但是，当我测试程序时，如果我输入exit，控制台就会中止该程序。有没有办法让我进入退出，然后程序调用{{1}}？

Answer 1

我认为代码中的这种变化将解决问题。请尝试使用此代码：

void printArray(string string_array[], int size){
    for (int i = 0; i < size; i++){
        cout << string_array[i];
    }

}
void a_func(){
    string string_array[10];
    string user_input;

    while (user_input != "exit"){
        cout << "Please enter a number between 0 - 100: ";
        cin >> user_input;
        if (user_input == "exit"){
            printArray(string_array, 10);
        }
        else if (stoi(user_input) < 0 || stoi(user_input) > 100){
            cout << "Error, please re-enter the number between 0 - 100: ";
            cin >> user_input;

            int array_index = stoi(user_input) / 10;
            string_array[array_index] = "*";
        }
    }
}

希望这有帮助

Answer 2

stoi不接受非数字。试试这个：

#include <iostream>
using namespace std;

void printArray(string string_array[], int size){
    for (int i = 0; i < size; i++){
        cout << string_array[i];
    }
}

void a_func(){
    string string_array[10];
    string user_input;

    while (user_input != "exit"){
        cout << "Please enter a number between 0 - 100: ";
        cin >> user_input;
        //cout << "You have printed " << user_input << endl;

        bool isNumber = true;
        for(string::const_iterator k = user_input.begin(); k != user_input.end(); ++k) {
            if (isdigit(*k) == false) {
                isNumber = false;
                break;
            }
        }

        if (isNumber) {
            int number = stoi(user_input);
            if (number < 0 || number > 100){
                cout << "Error, please re-enter the number between 0 - 100: ";
                continue;
            } else {
                int array_index = stoi(user_input) / 10;
                string_array[array_index] = "*";
            }
        } else if (user_input == "exit"){
            printArray(string_array, 10);
            break;
        } else {
            // Not a number and not "exit"; do nothing?
        }
    }
}

int main() {
    a_func();
    return 0;
}

采取＆＃34;退出＆＃34;作为C ++中的用户输入

2 个答案: