我想使用CardLayout类更改JFrame的JPanel。 我已经运行了this示例,但它确实有效。
现在我想用作动作监听器,JMenuItem;所以,如果我按下那个JMenuItem,我想用特定的面板来改变它。所以这是JFrame:
public class FantaFrame extends JFrame implements Observer {
private static final long serialVersionUID = 1L;
private JPanel cardPanel = new JPanel();
private CardLayout cardLayout = new CardLayout();
public FantaFrame(HashMap<String, JPanel> fantaPanels) {
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setTitle("FantaCalcio App");
setSize(500, 500);
cardPanel.setLayout(cardLayout);
setPanels(fantaPanels);
}
public void update(Observable o, Object arg) {
cardLayout.show(cardPanel, arg.toString());
}
private void setPanels(HashMap<String, JPanel> fantaPanels) {
for (String name : fantaPanels.keySet()) {
cardPanel.add(fantaPanels.get(name), name);
}
}
}
这些是菜单,控制器和主菜单:
private void pressed(){
home.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
controller.changePanel(home.getText());
}
});
}
public class Controller extends Observable {
public void changePanel(String panel){
setChanged();
notifyObservers(panel);
}
}
public static void main(String[] args) {
fantaPanels.put("Login", new LoginPanel());
Controller controller = new Controller();
MenuBarApp menuApp = new MenuBarApp(controller);
FantaFrame frame = new FantaFrame(fantaPanels);
frame.setJMenuBar(menuApp);
controller.addObserver(frame);
frame.setVisible(true);
}
问题在于JPanel没有改变。您认为这个问题是什么? 我已经调试过了,在update()方法中,正确的String值到了。
答案 0 :(得分:2)
你永远不会添加cardPanel JPanel,使用CardLayout并向任何东西显示“牌”。您需要将其添加到JFrame的contentPane中,以便显示任何内容。即,
public FantaFrame(HashMap<String, JPanel> fantaPanels) {
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setTitle("FantaCalcio App");
setSize(500, 500);
cardPanel.setLayout(cardLayout);
add(cardPanel, BorderLayout.CENTER); // ****** add this line ******
setPanels(fantaPanels);
}