Question

可能是一个简单的解决方法，但从我从示例中可以看到，这应该有效！

ALTER TABLE "relevant_topics" 
ADD `linktitle_11` varchar(500);
ADD `linktitle_11_url` varchar(500);
ADD `linktitle_11_desc` varchar(500);
ADD `linktitle_12` varchar(500);
ADD `linktitle_12_url` varchar(500);
ADD `linktitle_12_desc` varchar(500);
ADD `linktitle_13` varchar(500);
ADD `linktitle_13_url` varchar(500);
ADD `linktitle_13_desc` varchar(500);

谁能说出我做错了什么？

Answer 1

表格名称不需要引号，每个,应与ALTER TABLE relevant_topics ADD `linktitle_11` varchar(500), ADD `linktitle_11_url` varchar(500), ADD `linktitle_11_desc` varchar(500), ADD `linktitle_12` varchar(500), ADD `linktitle_12_url` varchar(500), ADD `linktitle_12_desc` varchar(500), ADD `linktitle_13` varchar(500), ADD `linktitle_13_url` varchar(500), ADD `linktitle_13_desc` varchar(500);

分开

Objective-C

Answer 2

因为现在你只是创建了linktitle_11列吗？分号结束你的sql语句，并且没有简单地称为add的sql语句，只要添加第一列，你的alter table语句就会结束你需要这样做：

ALTER TABLE "relevant_topics" 
ADD (`linktitle_11` varchar(500),
 `linktitle_11_url` varchar(500),
 `linktitle_11_desc` varchar(500),
 `linktitle_12` varchar(500),
 `linktitle_12_url` varchar(500),
 `linktitle_12_desc` varchar(500),
 `linktitle_13` varchar(500),
 `linktitle_13_url` varchar(500));

OR

ALTER TABLE "relevant_topics" 
ADD `linktitle_11` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_11_url` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_11_desc` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_12` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_12_url` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_12_desc` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_13` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_13_url` varchar(500);
ALTER TABLE "relevant_topics" 
ADD `linktitle_13_desc` varchar(500);

虽然我不知道哪种方式最安全

Answer 3

如果需要，您可以使用代字号作为引号

ALTER TABLE `relevant_topics`
ADD `linktitle_11` varchar(500),
ADD `linktitle_11_url` varchar(500),
ADD `linktitle_11_desc` varchar(500),
ADD `linktitle_12` varchar(500),
ADD `linktitle_12_url` varchar(500),
ADD `linktitle_12_desc` varchar(500),
ADD `linktitle_13` varchar(500),
ADD `linktitle_13_url` varchar(500),
ADD `linktitle_13_desc` varchar(500);

Answer 4

尝试

ALTER TABLE relevant_topics
ADD `linktitle_11` varchar(500),
ADD `linktitle_11_url` varchar(500),
ADD `linktitle_11_desc` varchar(500),
ADD `linktitle_12` varchar(500),
ADD `linktitle_12_url` varchar(500),
ADD `linktitle_12_desc` varchar(500),
ADD `linktitle_13` varchar(500),
ADD `linktitle_13_url` varchar(500),
ADD `linktitle_13_desc` varchar(500);

SQL中的语法错误？

4 个答案: