字符串变量中的第N个单词

Question

在Bash中，我想通过变量得到字符串的第N个字。

例如：

STRING="one two three four"
N=3

结果：

"three"

Bash命令/脚本可以做什么？

Answer 1

echo $STRING | cut -d " " -f $N

Answer 2

替代

N=3
STRING="one two three four"

arr=($STRING)
echo ${arr[N-1]}

Answer 3

使用awk

echo $STRING | awk -v N=$N '{print $N}'

测试

% N=3
% STRING="one two three four"
% echo $STRING | awk -v N=$N '{print $N}'
three

Answer 4

包含一些语句的文件：

cat test.txt

结果：

This is the 1st Statement
This is the 2nd Statement
This is the 3rd Statement
This is the 4th Statement
This is the 5th Statement

因此，要打印此语句的第四个单词：

cat test.txt |awk '{print $4}'

输出：

1st
2nd
3rd
4th
5th

Answer 5

STRING=(one two three four)
echo "${STRING[n]}"

Answer 6

没有昂贵的叉子，没有管道，没有基本原理：

$ set -- $STRING
$ eval echo \${$N}
three

但要注意全球化。