Question

我在我的项目中使用Parse.com。我想创建自己的实体类扩展Parse Object但我有一个java.lang.ClassCastException：com.parse.ParseObject无法强制转换为com.james.strongpeopleapp.Recipe

@ParseClassName("Recipe")
public class Recipe extends ParseObject {

    public Recipe() {
    }

    public String getRecipeName(){
        return getString("RecipeName");
    }

注册子类

public class ParseApp extends Application {

    @Override
    public void onCreate() {

        ParseObject.registerSubclass(Recipe.class);
        Parse.initialize(this, "XXXXXX", "XXXXXXX");

    }
}

异常发生在适配器

中的getItemView（）中

 public class MainParseAdapter extends ParseQueryAdapter<Recipe> {

private LayoutInflater layoutInflater;

public MainParseAdapter(Context context) {

    super(context, new QueryFactory<Recipe>() {
        @Override
        public ParseQuery<Recipe> create() {
            ParseQuery query = new ParseQuery("OwnRecipeBook");
            return query;
        }
    });

    layoutInflater = (LayoutInflater) context
            .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}

@Override
public View getItemView(Recipe recipe, View v, ViewGroup parent) {

    if(v == null){
        v = layoutInflater.inflate(R.layout.recipe_item, parent, false);
    }
    super.getItemView(recipe, v, parent);

    TextView mName = (TextView) v.findViewById(R.id.recipe_tw);
    mName.setText(recipe.getRecipeName());

    ParseImageView mImage = (ParseImageView) v.findViewById(R.id.recipe_imageView);
    mImage.setParseFile(recipe.getRecipeImage());
    mImage.loadInBackground();

    return v;
}

public String getItemIdFromTable(int position){
    return getItem(position).getObjectId();
}

}

Answer 1

比较一下：

@ParseClassName("Recipe")

对此：

ParseQuery query = new ParseQuery("OwnRecipeBook");

存在类型不匹配。尝试使用相同的名称。这些类型可能看起来与你完全相同，但是Parse需要准确，明确地知道你想要做什么。

类不能转换为ParseObject

1 个答案: