Question

我试图在用户登录FOSUserBundle后执行一个函数，在我的config.yml中我设置了服务：

services:
    authentication.success.listener:
        class: MyCompany\MyBundle\EventListener\AuthenticationEventListener
        arguments: [@router]
        tags:
            - { name: kernel.event_subscriber }

然后，我用方法创建Listener类：

<?php

namespace MyCompany\MyBundle\EventListener;

use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use FOS\UserBundle\FOSUserEvents;
use FOS\UserBundle\Event\UserEvent;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\Cookie as Cookie;

class AuthenticationEventListener implements EventSubscriberInterface
{    
    private $router;

    public function __construct(UrlGeneratorInterface $router)
    {
         $this->router = $router;
    }

    public static function getSubscribedEvents()
    {
        return array(
                FOSUserEvents::SECURITY_IMPLICIT_LOGIN => 'onAuthenticationSuccess',
        );
    }

    public function onAuthenticationSuccess(UserEvent $event)
    {
        //my actions goes here...
    }

}

?>

当我尝试登录时，之后没有任何反应，我写了一些错误的代码来生成异常，但一切顺利......显然这个功能并没有被排除在外。

请帮忙吗？

Answer 1

好吧，最后几个小时搜索并享受尤文图斯战胜皇家马德里队（2-1）后，我找到了一个解决方案。我的解决方案是修改＆＃39; success_handler＆＃39;在security.yml中创建事件，这是代码：

security:
    ..
    firewalls:
        main: 
        ..
        success_handler: authentication.success.listener

然后在services.yml中声明服务：

services:
    authentication.success.listener:
        class: MyCompany\MyBundle\EventListener\AuthenticationEventListener
        arguments: ['@router', '@security.context', '@service_container']

然后我宣布要听的类/函数：

// MyCompany\MyBundle\EventListener\AuthenticationEventListener.php

<?php

namespace MyCompany\MyBundle\EventListener;

use Symfony\Component\Security\Http\Authentication\AuthenticationSuccessHandlerInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Routing\Router;    

class AuthenticationEventListener implements AuthenticationSuccessHandlerInterface
{    
    protected $router;
    protected $security;
    protected $container;
    protected $em;

    public function __construct(Router $router, SecurityContext $security, $container)
    {
        $this->router = $router;
        $this->security = $security;
        $this->container = $container;
        $this->em = $this->container->get('doctrine')->getEntityManager();
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token)
    {
        $response = new Response();
        $response = new RedirectResponse('dashboard');
        return $response;
    }

}

?>

我希望它对你们有用......

非常感谢！

Answer 2

试试这段代码：

public static function getSubscribedEvents()
{
    return array(
        FOSUserEvents::SECURITY_IMPLICIT_LOGIN => array('onAuthenticationnSuccess',0)
    );
}

这应该是这里记录的语法：http://symfony.com/doc/current/components/event_dispatcher/introduction.html

用户登录Symfony 2.3后执行功能

2 个答案: