<PrintLetterBarcodeData uid="229636134720" name="Nandan Mohan Nilekani"
gender="M" yob="1955" house="856, 13th Main , 3rd Block"
loc="Koramangala" vtc="Bangalore South" po="Koramangala"
dist="Bangalore" state="Karnataka" pc="560034"/>
我想将上面的字符串拆分为
uid="229636134720"
name="Nandan Mohan Nilekani"
gender="M"
yob="1955"
house="856, 13th Main , 3rd Block"
loc="Koramangala"
vtc="Bangalore South"
po="Koramangala"
dist="Bangalore"
state="Karnataka"
pc="560034"
我尝试过但未能像那样做
答案 0 :(得分:1)
看看这个:
NSString *testString = @"<PrintLetterBarcodeData uid=\"229636134720\" name=\"Nandan Mohan Nilekani\" gender=\"M\" yob=\"1955\" house=\"856, 13th Main , 3rd Block\" loc=\"Koramangala\" vtc=\"Bangalore South\" po=\"Koramangala\" dist=\"Bangalore\" state=\"Karnataka\" pc=\"560034\"/>";
NSRegularExpression *regex = [[NSRegularExpression alloc] initWithPattern:@" \\w+=\".+?\"" options:0 error:nil];
[regex enumerateMatchesInString:testString options:0 range:NSMakeRange(0, testString.length) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSLog(@"%@", [testString substringWithRange:result.range]);
}];
答案 1 :(得分:-1)
我是
首先删除
'<PrintLetterBarcodeData' and '/>'
然后用换行符替换'“',即引号空格。
希望你没有'val =“”',即一个以空白开头的值。
最好是正则表达式,匹配word =“val”。