Question

我创建了一个带有“XSD.exe”的Structure类，现在我遇到了一个简短的问题：

我在结构中有5个不同的“类”，所有5个类都具有相同的值：

public partial class Carrier
{

    private string codeField;

    private string companyField;

    private string legalNameField;

    private string addressField;

    private string address2Field;

    private string stateField;

    private string cityField;

    private string countryField;

    private string phoneField;

    private string faxField;

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Code
    {
        get
        {
            return this.codeField;
        }
        set
        {
            this.codeField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Company
    {
        get
        {
            return this.companyField;
        }
        set
        {
            this.companyField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string LegalName
    {
        get
        {
            return this.legalNameField;
        }
        set
        {
            this.legalNameField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Address
    {
        get
        {
            return this.addressField;
        }
        set
        {
            this.addressField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Address2
    {
        get
        {
            return this.address2Field;
        }
        set
        {
            this.address2Field = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string State
    {
        get
        {
            return this.stateField;
        }
        set
        {
            this.stateField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string City
    {
        get
        {
            return this.cityField;
        }
        set
        {
            this.cityField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Country
    {
        get
        {
            return this.countryField;
        }
        set
        {
            this.countryField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Phone
    {
        get
        {
            return this.phoneField;
        }
        set
        {
            this.phoneField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string Fax
    {
        get
        {
            return this.faxField;
        }
        set
        {
            this.faxField = value;
        }
    }
}

我想将所有五个不同的对象设置为另一个对象：

 private Adress FindAddresses(Carrier address)
    {
        tempAddress = new Address();
        tempAddress.AddressCode = address.Code;
        tempAddress.Name1 = address.LegalName;
        tempAddress.Name2 = address.Address;
        tempAddress.Name3 = address.Address2;
        return tempAddress;
    }

唯一的方法是将此功能重载5次或提供“更好”的方法吗？

Answer 1

您可以让类实现相同的接口，例如IAdressable：

public interface IAddressable
{
    public AddressCode Code { get; set; }
    public string LegalName { get; set; }
    public string Address { get; set; }
    public string Address2 { get; set; }
}

现在该方法可以将IAddressable作为参数：

 private Adress FindAddresses(IAddressable address)
{
    var tempAddress = new Address();
    tempAddress.AddressCode = address.Code;
    tempAddress.Name1 = address.LegalName;
    tempAddress.Name2 = address.Address;
    tempAddress.Name3 = address.Address2;
    return tempAddress;
}

然后你可以用你的所有类调用这个方法，因为它们都实现了那个接口。

Answer 2

您可以尝试将公共属性移动到公共基类中，并从该基类派生Carrier和其他4个类。

然后，这些方法将获取基类的实例。

public class BaseAddressClass
{
    ...
}

public class Carrier : BaseAddressClass
{
    // Other fields
}

private Address FindAddress(BaseAddressClass address)
{
    ...
}

5个不同的对象，其值与函数

2 个答案: