这是我尝试过的:
$image = "images/20100609124341Chrysanthemum.jpg";
$degrees = 40;
// Content type
header('Content-type: image/jpeg');
// Load
$source = imagecreatefromjpeg($filename);
// Rotate
$rotate = imagerotate($source, $degrees, 0);
// Output
imagejpeg($rotate);
......但我没有输出。谁能告诉我这有什么问题?