Question

我有一个简单的架构：

CREATE TABLE technologies (
  technologyName VARCHAR(50) NOT NULL PRIMARY KEY
);

CREATE TABLE technologySynonyms (
  synonymId              INT PRIMARY KEY AUTO_INCREMENT,
  sourceTechnologyName VARCHAR(50) UNIQUE,
  targetTechnologyName VARCHAR(50),
  FOREIGN KEY (targetTechnologyName) 
    REFERENCES technologies(technologyName)
);

我想进一步简化technologySynonyms表定义：

CREATE TABLE technologySynonyms (
  synonymId              INT PRIMARY KEY AUTO_INCREMENT,
  sourceTechnologyName VARCHAR(50) UNIQUE,
  targetTechnologyName VARCHAR(50) REFERENCES technologies(technologyName)
);

我没有错误 - 查询执行正常并且创建了表，但是当我插入一个验证外键约束的记录时：

INSSERT INTO technologySynonyms (sourceTechnologyName, targetTechnologyName)
  VALUES ('JS', 'Value not present in technologies table!!');

插入记录。

这给我留下了几个问题：

我的SQL出了什么问题？这不行吗？
我可以使MySQL Workbench更严格吗？如果查询被立即拒绝，我会更喜欢它。

Answer 1

这是标准行为，请阅读重要部分

Furthermore, MySQL parses but ignores “inline REFERENCES specifications” (as defined in the SQL standard) where the references are defined as part of the column specification. MySQL accepts REFERENCES clauses only when specified as part of a separate FOREIGN KEY specification

内联

1 个答案: