我知道如何单独处理左键或右键，拖动，双击，但如果用户同时点击鼠标左键和鼠标键而不干扰/我就无法弄清楚如何做某事导致其他事件发生。
@Override
public void handle(Event event) {
if (event.getSource() instanceof Tile) {
Tile tile = (Tile) event.getSource();
if (event.getEventType().equals(MouseEvent.MOUSE_CLICKED)) {
if (((MouseEvent) event).getButton().equals(MouseButton.SECONDARY))
tile.toggleFlag();
else if (((MouseEvent) event).getClickCount() == 2)
mineField.massClick(tile);
}
if (event.getEventType().equals(MouseEvent.DRAG_DETECTED))
if (!((MouseEvent) event).getButton().equals(MouseButton.SECONDARY))
tile.startFullDrag();
if (event.getEventType().equals(MouseDragEvent.MOUSE_DRAG_ENTERED))
tile.arm();
if (event.getEventType().equals(MouseDragEvent.MOUSE_DRAG_EXITED))
tile.disarm();
if (event.getEventType().equals(MouseDragEvent.MOUSE_DRAG_RELEASED))
mineField.clickedTile(tile);
if (event.getEventType().equals(ActionEvent.ANY))
mineField.clickedTile(tile);
}
}
此外，如果您发现我的代码存在问题，请随时指出，并始终寻求改进。
答案 0 :(得分：3)
简单版本是：
public class Main extends Application {
@Override
public void start(Stage primaryStage) {
try {
StackPane root = new StackPane();
root.addEventFilter(MouseEvent.MOUSE_PRESSED, e -> {
if( e.isPrimaryButtonDown() && e.isSecondaryButtonDown()) {
System.out.println( "Both down");
} else if( e.isPrimaryButtonDown()) {
System.out.println( "Primary down");
} else if( e.isSecondaryButtonDown()) {
System.out.println( "Secondary down");
}
});
Scene scene = new Scene(root,400,400);
primaryStage.setScene(scene);
primaryStage.show();
} catch(Exception e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
launch(args);
}
}
如果您希望在按下两个按钮时发生自己的事件，可以这样尝试：
public class Main extends Application {
BooleanProperty primaryMouseButtonDown = new SimpleBooleanProperty();
BooleanProperty secondaryMouseButtonDown = new SimpleBooleanProperty();
@Override
public void start(Stage primaryStage) {
try {
StackPane root = new StackPane();
root.addEventFilter(MouseEvent.MOUSE_PRESSED, e -> {
primaryMouseButtonDown.setValue( e.isPrimaryButtonDown());
secondaryMouseButtonDown.setValue( e.isSecondaryButtonDown());
});
root.addEventFilter(MouseEvent.MOUSE_RELEASED, e -> {
primaryMouseButtonDown.setValue( e.isPrimaryButtonDown());
secondaryMouseButtonDown.setValue( e.isSecondaryButtonDown());
});
BooleanBinding binding = Bindings.and(primaryMouseButtonDown, secondaryMouseButtonDown);
binding.addListener( new ChangeListener<Boolean>() {
@Override
public void changed(ObservableValue<? extends Boolean> observable, Boolean oldValue, Boolean newValue) {
System.out.println( "Mouse Button Event: " + oldValue + " -> " + newValue);
}
});
Scene scene = new Scene(root,400,400);
primaryStage.setScene(scene);
primaryStage.show();
} catch(Exception e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
launch(args);
}
}
有2个布尔属性，一个用于主按钮向下，一个用于辅助按钮向下。两个属性都通过BooleanBinding连接。只要其中一个属性通过鼠标事件更改，就会触发一个事件。那么剩下要做的就是检查newValue是否为真并触发你的处理代码。
答案 1 :(得分：1)
执行更多操作，观察鼠标按下，并在为鼠标左键/右键调用mousePressed事件时将布尔值设置为true。然后在事件中看看是否左右两个布尔都是真的。如果是的话，就像对它们同时按下一样。
boolean mouse_1, mouse_2 = false;
public void mousePressed(MouseEvent e){
//The numbers are just made up I don't remember the actual codes for the buttons but it's simple enough to figure out.
if(e.getButton()==1){
mouse_1 = true;
}
if(e.getButton()==2){
mouse_2 = true;
}
if(mouse_1&&mouse_2){
//Your code here
}
}
public void mouseReleased(MouseEvent e){
if(e.getButton() == 1){
mouse_1 = false;
}
if(e.getButton() == 2){
mouse_2 = false;
}
}
假设这是某种处理程序类......但这是如何实现它的简称。
答案 2 :(得分：1)
我可能迟到了回答这个问题，但我要发布我的解决方案，以便演示如何同时处理单键按钮，同时点击两个按钮
现有答案已经解释了如何检测同时点击的两个鼠标按钮。但鼠标事件（点击，按下和释放）仍由单个按钮触发，之前的海报并未解决如何避免这些事件相互干扰的问题。
我的解决方案是跟踪鼠标按下时按下的两个按钮，并在鼠标释放时检测任何类型的鼠标点击：
//flag to track both buttons being pressed
private boolean wereBothButtonsPressed = false;
private void onMousePressed(MouseEvent e) {
//single button press sets flag to false
wereBothButtonsPressed = e.isPrimaryButtonDown() && e.isSecondaryButtonDown();
}
private void onMouseReleased(MouseEvent e) {
if (e.isPrimaryButtonDown() || e.isSecondaryButtonDown()) {
//do nothing if user is still holding the button
return;
}
if (wereBothButtonsPressed) {
System.out.prinln("Both buttons");
} else if (e.getButton() == MouseButton.PRIMARY) {
System.out.prinln("Only primary");
} else if (e.getButton() == MouseButton.SECONDARY) {
System.out.prinln("Only secondary");
}
}
您可以为特定控件上的特定事件设置这些处理程序，或使其适合您的方法：
private boolean wereBothButtonsPressed = false;
@Override
public void handle(Event event) {
...
if (event.getEventType().equals(MouseEvent.MOUSE_PRESSED)) {
MouseEvent me = (MouseEvent) event;
wereBothButtonsPressed = me.isPrimaryButtonDown() && me.isSecondaryButtonDown();
} else if (event.getEventType().equals(MouseEvent.MOUSE_RELEASED)) {
MouseEvent me = (MouseEvent) event;
if (!me.isPrimaryButtonDown() && !me.isSecondaryButtonDown()) {
if(wereBothButtonsPressed) {
mineField.massClick(tile);
} else if(me.getButton() == MouseButton.PRIMARY) {
mineField.clickedTile(tile);
} else if(me.getButton() == MouseButton.SECONDARY) {
tile.toggleFlag();
}
}
...