here is my code sample:
if os.path.exists(inputdir):
for file in os.listdir(inputdir):
print file
So when I print the files, files that do not actually exist in the input directory are printed so when I try to use the file it cannot open it. What could be causing this issue?
EDIT: Out of 8,831 files at the beginning this gets printed:
0004872bda8db3ea40167b887108e9a3.xml
0007cba714860a090922cec6132442a4.xml
0009f949eba51c5d2936458595040135.xml
When the actual files are:
000cbd88e8868d56aa7eb7a7e3e90166.xml
00a270aa4d18f139d0405604df200c61.xml
00a39768b77e83f86bd3cd81bf5a9cfb.xml
And at the end the files are identical. I'm not sure at what point it changes.
答案 0 :(得分:-1)
这应该有效:
import os
for entry in sorted(os.listdir(inputdir)):
filename = os.path.join(inputdir, entry)
print(filename)
os.lstat(filename)
如果您的系统没有os.lstat
,请尝试os.stat
。
获得No such file or directory
的一个可能原因是filename
是指向不存在文件的符号链接。