SpiraTest JUnit集成库是否支持参数化测试?

时间:2015-05-04 17:13:37

标签: java junit spiratest

我正在使用Spiratest JUnit集成库。它正常的测试用例正常工作,测试结果按预期传输到SpiraTest。

现在,我正在添加参数化测试,这是JUnit 4的一个功能。当我将SpiraTest注释添加到参数化测试中,并使用SpiraTest自动测试集成指南中记录的Main类运行它时,它失败。我收到以下错误消息: java.lang.NoSuchMethodException:org.test.FibonacciTest.test0

SpiraTest JUnit集成库是否支持参数化测试?如果是,我如何在SpiraTest JUnit集成库中使用参数化测试?

这是我的代码,让您了解我尝试完成的任务:

  @RunWith(Parameterized.class)
  @SpiraTestConfiguration(url = URL, login = USER, password = PWD, projectId = PROJECT_ID)
  public class FibonacciTest {

    @Parameters
    public static Collection<Object[]> data() {
        return Arrays.asList(new Object[][] { { 0, 0 }, { 1, 1 }, { 2, 1 }, { 3, 2 }, { 4, 3 }, { 5, 5 }, { 6, 8 } });
    }

    private int fInput;

    private int fExpected;

    public FibonacciTest(int input, int expected) {
        fInput = input;
        fExpected = expected;
    }

    @Test
    @SpiraTestCase(testCaseId=21966)
    public void test() {
        assertEquals(fExpected, compute(fInput));
    }

    private int compute(int fInput2) {
        return 1;
    }
  }

这是主要课程:

public class SpiraApplicationMain {    
    public final static String URL = "";
    public final static String USER = ";
    public final static String PWD = "";
    public final static int PROJECT_ID = 0;

    /**
     * Entry point for command line execution
     * 
     * @param args
     *            The command line arguments
     */
    public static void main(String[] args) {
        // Instantiate the JUnit core
        JUnitCore core = new JUnitCore();

        // Add the custom SpiraTest listener
        core.addListener(new SpiraTestListener());

        // Finally run the test fixture
        core.run(FibonacciTest.class);
    }

    /**
     * Entry point for JUnit 4.x runners
     *
     * @return Handle to the test framework
     */
    public static junit.framework.Test suite() {
        return new JUnit4TestAdapter(FibonacciTest.class);
    }
}

1 个答案:

答案 0 :(得分:0)

Adam from Inflectra

解释说,Spiratest集成库没有考虑到这一功能而开发