我有以下架构:
{"<UserInformation xmlns=''> was not expected."}
我需要var data = {"Books:"....};
var indianBooks = _.filter(data.Books.History, function(book) { return _.contains(book.Tags, "Indian"); })
对象的Json为
public class Student {
String name;
List<Integer> sequence;
}
The documentation没有明确说明如何为集合编写序列化程序。
答案 0 :(得分:3)
您可以创建TypeAdapter
,例如:
public static class StudentAdapter extends TypeAdapter<Student> {
public void write(JsonWriter writer, Student student)
throws IOException {
if (student == null) {
writer.nullValue();
return;
}
writer.beginObject();
writer.name("name");
writer.value(student.name);
writer.name("sequence");
writeSequence(writer, student.sequence);
writer.endObject();
}
private void writeSequence(JsonWriter writer, List<Integer> seq)
throws IOException {
writer.beginObject();
for (int i = 0; i < seq.size(); i++) {
writer.name("index_" + i);
writer.value(seq.get(i));
}
writer.endObject();
}
@Override
public Student read(JsonReader in) throws IOException {
// This is left blank as an exercise for the reader
return null;
}
}
然后用
注册GsonBuilder b = new GsonBuilder();
b.registerTypeAdapter(Student.class, new StudentAdapter());
Gson g = b.create();
如果您使用示例学生运行此操作:
Student s = new Student();
s.name = "John Smith";
s.sequence = ImmutableList.of(1,3,4,7); // This is a guava method
System.out.println(g.toJson(s));
输出:
{"name":"John Smith","sequence":{"index_0":1,"index_1":3,"index_2":4,"index_3":7}}
答案 1 :(得分:0)
GSON支持自定义FieldNamingStrategy
:
new GsonBuilder().setFieldNamingStrategy(new FieldNamingStrategy() {
@Override
public String translateName(java.lang.reflect.Field f) {
// return a custom field name
}
});
但这显然不能涵盖您的情况,我能想到的一个简单的解决方法是制作您的sequence
列表transient
并拥有实际< / em>带有GSON校正数据的序列图:
public class Student {
String name;
transient List<Integer> sequenceInternal;
Map<String, Integer> sequence;
}
当您的sequenceInternal
对象发生更改时,请将更改写入序列图。