期望的输出：

Question

这是我要处理的示例文件。我想过使用关键字＆＃34; description＆＃34;作为某种RS，但不知道如何做到这一点，也不是一致的。

背景：我正在处理一个日志文件，其中包含第一行中的日期/时间戳（APR12），第二行中有关于日志的描述。这种描述适用于少数几个日志和missig。

001 APR12 aaa bbb
Description: This is a test file.
002 APR12 aaa bbb
Description: This is another test file.
003 APR12 aaa XXX
004 APR12 aaa bbb
Description: This is another,after skipping one.

期望的输出：

001 APR12 aaa bbb Description: This is a test file.
002 APR12 aaa bbb Description: This is another test file.
003 APR12 aaa XXX
004 APR12 aaa bbb Description: This is another,after skipping one.

Answer 1

$ awk '{printf "%s%s", (/^[0-9]/?rs:FS), $0; rs=RS} END{print ""}' file
001 APR12 aaa bbb Description: This is a test file.
002 APR12 aaa bbb Description: This is another test file.
003 APR12 aaa XXX
004 APR12 aaa bbb Description: This is another,after skipping one.

Answer 2

每当当前行不以＆＃34开头时，您可以添加换行符;说明＆＃34;：

awk 'NR>1 && !/^Description/{print ""}{printf "%s ", $0}' file

NR>1阻止在输出开头添加换行符。

如果处理了任何行，您可能还需要添加END块以在输出的末尾添加换行符：END{if(NR)print ""}。

Answer 3

这可能适合你（GNU sed）：

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;

public class LabelColourExample {

    private Timer timer;
    private JLabel label;
    private Color [] colours = { 
        Color.red,
        Color.blue,
        Color.green,
        Color.cyan,
        Color.yellow,
        Color.magenta,
        Color.black,
        Color.white
    };
    private int counter;

    private static final int GAP = 5;   

    private ActionListener timerActions = new ActionListener () {
        @Override
        public void actionPerformed ( ActionEvent ae ) {
            label.setForeground ( colours [ counter++ ] );
            counter %= colours.length;
        }
    };

    public LabelColourExample () {
        counter = 0;
    }

    private void displayGUI () {        
        JFrame frame = new JFrame ( "Label Colour Example" );
        frame.setDefaultCloseOperation ( JFrame.DISPOSE_ON_CLOSE );

        JPanel contentPane = new JPanel ();
        contentPane.setLayout ( new BorderLayout ( GAP, GAP ) );

        label = new JLabel ( "MyName", JLabel.CENTER );
        label.setOpaque ( true );
        contentPane.add ( label, BorderLayout.CENTER );

        JButton button = new JButton ( "Stop" );
        button.addActionListener ( new ActionListener () {
            @Override
            public void actionPerformed ( ActionEvent ae ) {
                JButton button = ( JButton ) ae.getSource ();
                if ( timer.isRunning () ) {
                    timer.stop ();
                    button.setText ( "Start" );
                } else {
                    timer.start ();
                    button.setText ( "Stop" );
                }
            }
        } );
        contentPane.add ( button, BorderLayout.PAGE_END );

        frame.setContentPane ( contentPane );
        frame.pack ();
        frame.setLocationByPlatform ( true );
        frame.setVisible ( true );

        timer = new Timer ( 1000, timerActions );
        timer.start ();
    }

    public static void main ( String[] args ) {
        Runnable runnable = new Runnable () {
            @Override
            public void run () {
                new LabelColourExample ().displayGUI ();
            }
        };
        EventQueue.invokeLater ( runnable );
    }
}

读取整个文件中的线对，如果对中的第二行开始sed 'N;s/\n\(Description\)/ \1/;P;D' file，则用空格替换换行符。

Answer 4

sed ':a
N;$!ba
s/\n\([^0-9]\)/ \1/g' YourFile

直到你没有巨大的文件（加载到内存中）。
加入不以数字

如果你在4.2.2之后有一个允许-z（-Z option）的GNU sed版本。感谢@JJoao提供此优化代码。

sed -z 's/\n\(^[0-9]\)/ \1/g' YourFile

Answer 5

可能过于复杂，但这里有sed的解决方案：

# Does the line contain description?

# Yes ...
/Description/{
    # Exchange hold and pattern space
    x
    # Append hold space to pattern space
    # separated by newline 
    G
    # Remove that newline by a space
    s/\n\+/ /gp 
}

# No ...
/Description/! {
    # Exchange hold and pattern buffer
    x
    # The hold buffer contains a prefix line
    /Description/! {
        # Print it
        p
    }
    # Exchange hold and pattern buffer again
    x
    # Store current line in the hold buffer   
    h   
}

Answer 6

perl -p0e 's!\n(?=Des)! !g'

（未经测试） - 它将所有文件加载到内存中......

在找到模式时将行转置为列

期望的输出：

6 个答案: