Question

我正在制作一个Android应用程序，需要检测设备电源按钮事件按两次/三次＆amp;在后台发送短信。监听器应该在后台运行（即使我的应用程序未打开，它应该检测到按键事件并相应地采取行动）。

以下是我尝试过的代码无效......

我的代码：

public class MyBroadCastReciever extends BroadcastReceiver {

     int Count=0;

     @Override
        public void onReceive(Context context, Intent intent) {
            if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
               Count++;
               if(Count==2){
                  //Send SMS code..
                 }


            } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
                 //This is for screen ON option.
            }
        }

清单文件：

  <application
       android:icon="@drawable/ic_launcher"
       android:label="@string/app_name"
       android:theme="@style/AppTheme" >


    <receiver android:name=".MyBroadCastReciever" >
        <intent-filter>
            <action android:name="android.intent.action.SCREEN_OFF" />
            <action android:name="android.intent.action.SCREEN_ON" />
        </intent-filter>
    </receiver>
</application>

Answer 1

这是我用来检测用户是否在场，屏幕打开/关闭的代码。

AndroidManifest.xml

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.example.userpresent"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk
        android:minSdkVersion="8"
        android:targetSdkVersion="21" />


    <application
        android:allowBackup="true"
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >
        <activity
            android:name="com.example.userpresent.MainActivity"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>

            <service android:name="com.example.userpresent.LockService" >
                <intent-filter>
                    <action android:name="android.intent.action.BOOT_COMPLETED" />
                </intent-filter>
            </service>
    </application>

</manifest>

MainActivity.java

package com.example.userpresent;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;

 public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

startService(new Intent(getApplicationContext(), LockService.class));


   }
}

LockService.java

package com.example.userpresent;

import android.app.Service;
import android.content.BroadcastReceiver;
import android.content.Intent;
import android.content.IntentFilter;
import android.os.Binder;
import android.os.IBinder;

public class LockService extends Service {

@Override
public IBinder onBind(Intent intent) {
return null;
}

@Override
public void onCreate() {
super.onCreate();
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
final IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
filter.addAction(Intent.ACTION_SCREEN_OFF);
filter.addAction(Intent.ACTION_USER_PRESENT);
final BroadcastReceiver mReceiver = new ScreenReceiver();
registerReceiver(mReceiver, filter);
return super.onStartCommand(intent, flags, startId);
}
public class LocalBinder extends Binder {
LockService getService() {
return LockService.this;
}
}
}

ScreenReceiver.java

package com.example.userpresent;

import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.net.Uri;
import android.util.Log;

public class ScreenReceiver extends BroadcastReceiver {

    public static boolean wasScreenOn = true;

    @Override
    public void onReceive(final Context context, final Intent intent) {
    Log.e("LOB","onReceive");
        if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
            // do whatever you need to do here
            wasScreenOn = false;
            Log.e("LOB","wasScreenOn"+wasScreenOn);
        } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
            // and do whatever you need to do here
            wasScreenOn = true;

        }else if(intent.getAction().equals(Intent.ACTION_USER_PRESENT)){
            Log.e("LOB","userpresent");
            Log.e("LOB","wasScreenOn"+wasScreenOn);
            String url = "http://www.stackoverflow.com";
            Intent i = new Intent(Intent.ACTION_VIEW);
            i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            i.setData(Uri.parse(url)); 
            context.startActivity(i); 
        }
    }
}

Answer 2

这是我做过的事，

short description：您只需检测屏幕turn off和turns on何时计算它们之间的时差，如果它少于4秒（in my case）发送消息别的没有。

P.S-您可以更改pressing of power buttons的间隔。

在BroadcastReceiver：

中使用它

@Override
public void onReceive(final Context context, final Intent intent) {
 cntx = context;
 vibe = (Vibrator) context.getSystemService(Context.VIBRATOR_SERVICE);
 Log.v("onReceive", "Power button is pressed.");
 if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
  a = System.currentTimeMillis();
  seconds_screenoff = a;
  OLD_TIME = seconds_screenoff;
  OFF_SCREEN = true;

  new CountDownTimer(5000, 200) {

   public void onTick(long millisUntilFinished) {


    if (ON_SCREEN) {
     if (seconds_screenon != 0 && seconds_screenoff != 0) {

      actual_diff = cal_diff(seconds_screenon, seconds_screenoff);
      if (actual_diff <= 4000) {
       sent_msg = true;
       if (sent_msg) {

        Toast.makeText(cntx, "POWER BUTTON CLICKED 2 TIMES", Toast.LENGTH_LONG).show();
        vibe.vibrate(100);
        seconds_screenon = 0 L;
        seconds_screenoff = 0 L;
        sent_msg = false;

       }
      } else {
       seconds_screenon = 0 L;
       seconds_screenoff = 0 L;

      }
     }
    }
   }

   public void onFinish() {

    seconds_screenoff = 0 L;
   }
  }.start();



 } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
  a = System.currentTimeMillis();
  seconds_screenon = a;
  OLD_TIME = seconds_screenoff;

  new CountDownTimer(5000, 200) {

   public void onTick(long millisUntilFinished) {
    if (OFF_SCREEN) {
     if (seconds_screenon != 0 && seconds_screenoff != 0) {
      actual_diff = cal_diff(seconds_screenon, seconds_screenoff);
      if (actual_diff <= 4000) {
       sent_msg = true;
       if (sent_msg) {

        Toast.makeText(cntx, "POWER BUTTON CLICKED 2 TIMES", Toast.LENGTH_LONG).show();
        vibe.vibrate(100);
        seconds_screenon = 0 L;
        seconds_screenoff = 0 L;
        sent_msg = false;



       }
      } else {
       seconds_screenon = 0 L;
       seconds_screenoff = 0 L;

      }
     }
    }

   }

   public void onFinish() {

    seconds_screenon = 0 L;
   }
  }.start();



 }
}

private long cal_diff(long seconds_screenon2, long seconds_screenoff2) {
 if (seconds_screenon2 >= seconds_screenoff2) {
  diffrence = (seconds_screenon2) - (seconds_screenoff2);
  seconds_screenon2 = 0;
  seconds_screenoff2 = 0;
 } else {
  diffrence = (seconds_screenoff2) - (seconds_screenon2);
  seconds_screenon2 = 0;
  seconds_screenoff2 = 0;
 }

 return diffrence;
}

}

的manifest.xml

<receiver android:name=".MyReceiver" >
   <intent-filter>
     <action android:name="android.intent.action.ACTION_SHUTDOWN" >
     </action>
   </intent-filter>
</receiver>

<service
   android:name=".MyService"
   android:exported="false" />

将其粘贴到application代码

中

它对我来说很好 在后台

Answer 3

请检查：Power Button

并且：Press Power Button

static int i=0;
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (event.getKeyCode() == KeyEvent.KEYCODE_POWER) {
       i++;
        if(i==2){
    //do something

//at the end again i=0;
        }

    }
    return super.onKeyDown(keyCode, event);
}

Answer 4

试试这个......

public boolean onKeyDown(int code, KeyEvent keyEvent) {
        if (keyEvent.getKeyCode() == KeyEvent.KEYCODE_POWER) {

            // Your Logic Is Here
            return true;
        }
        return super.onKeyDown(code, keyEvent);
    }

如何在android中以编程方式检测设备电源按钮两次

4 个答案: