Question

假设我有一个逗号分隔的字符串，如下所示：

array
(
  [1] => Sunday,
  [2] => Monday,
  [3] => Tuesday,
  [4] => Wednesday,
  [5] => Thursday,
  [6] => Friday,
  [7] => Saturday,
);

如何在PHP中使用成对数组，如下所示 -

yourArray.sort({$0.date.timeIntervalSinceNow < $1.date.timeIntervalSinceNow})

Answer 1

简单回答（需要PHP＆gt; = 5.5.0）：如果您不需要在每个值的末尾使用尾随逗号

let lotoArray = lotoDictionary.allObjects as [Loto]

lotoArray.sort { $0.hafta < $1.hafta }

如果确实需要尾随逗号，可以添加：

$string = '1,Sunday,2,Monday,3,Tuesday,4,Wednesday,5,Thursday,6,Friday,7,Saturday';

$data = array_chunk(
    explode(',', $string),
    2
);
$newArray = array_combine(
    array_column($data, 0),
    array_column($data, 1)
);
var_dump($newArray);

Answer 2

如果您有像工作日和工作日数字这样的静态数据，那么使用静态数组肯定是最简单的：

$weekdays = array(
    1 => 'Sunday',
    2 => 'Monday',
    3 => 'Tuesday',
    4 => 'Wednesday',
    5 => 'Thursday',
    6 => 'Friday',
    7 => 'Saturday',
);

如果你有来解析逗号分隔的字符串，你可以使用它：

$string = '1,Sunday,2,Monday,3,Tuesday,4,Wednesday,5,Thursday,6,Friday,7,Saturday';
$parts = explode(',', $string);
$weekdays = array();

for ($i = 0; $i < count($parts); ) {
    $weekdays[$parts[$i]] = $parts[++$i];
    ++$i;
}

print_r($weekdays);

输出：

Array
(
    [1] => Sunday
    [2] => Monday
    [3] => Tuesday
    [4] => Wednesday
    [5] => Thursday
    [6] => Friday
    [7] => Saturday
)

它很漂亮，但它完成了工作:)。

Answer 3

这将为你工作。

$string = '1,Sunday,2,Monday,3,Tuesday,4,Wednesday,5,Thursday,6,Friday,7,Saturday.';
$dtd = explode(',', $string);
$array = array();
$i = 1;
foreach ($dtd as $key => $value){
    if($key % 2 == 1){
        $array[$i++] = $value;
    }
}

print_r($array);//Array ( [1] => Sunday [2] => Monday [3] => Tuesday [4] => Wednesday [5] => Thursday [6] => Friday [7] => Saturday. )

从逗号分隔的字符串生成两列数组

3 个答案: