Question

我有一份客户历史数据列表，其中也包含电话号码。我需要根据我的电话号码列表过滤历史数据，这是我的代码

历史课

0(1)

我从api call

获取消息历史记录列表

 public class MessengerHistory
    {
        public Int64 ClientId;
        public string FirstName;
        public string LastName;
        public string ChartNumber;
        public string PhoneNumber;
        public string PetName;
        public string Messagetext;
    }

List<string> phonenumber = List<string>{ "12345","45678","35487"}

我想过滤var messageOverview = messengerAppWorkflow.GetMessageOverview(); List<MessageHistroy> mHistory = messageOverview.messages.Select(item => item.clientPhone).ToList();值，以使用mHistory返回与phonenumber列表匹配的历史值。

Answer 1

你可以加入他们：

var query = from msg in messengerAppWorkflow.GetMessageHistory()
            join phone in phonenumber
            on msg.PhoneNumber equals phone
            select msg;
List<MessageHistroy> mHistory = query.ToList();

另一种less efficient方式正在使用Enumerable.Where + Contains：

List<MessengerHistory> mHistory = messengerAppWorkflow.GetMessageHistory()
    .Where(msg => phonenumber.Contains(msg.PhoneNumber))
    .ToList():

Answer 2

//这就是你已经拥有的

json_encode($array, JSON_NUMERIC_CHECK);

//假设messengerHistoryList是你从api获得的列表：

        List<MessengerHistory> reqMessengerHistoryList = new List<MessengerHistory>();

        List<string> phoneNumberList = new List<string> { "12345", "45678", "35487" };

//这就是你需要做的事情：

        List<MessengerHistory> messengerHistoryList = new List<MessengerHistory>();
        MessengerHistory messengerHistory1 = new MessengerHistory
        {
            ClientId = 123,
            FirstName = "Rahul",
            LastName = "Manhotra",
            ChartNumber = "abc",
            PhoneNumber = "12345",
            PetName = "pqr",
            Messagetext = "This is simple"
        };
        MessengerHistory messengerHistory2 = new MessengerHistory
        {
            ClientId = 123,
            FirstName = "Peter",
            LastName = "stuv",
            ChartNumber = "abc",
            PhoneNumber = "34534",
            PetName = "stu",
            Messagetext = "This is hard"
        };
        messengerHistoryList.Add(messengerHistory1);
        messengerHistoryList.Add(messengerHistory2);

使用另一个值列表过滤linq

2 个答案: