Question

我想在建议之前在Spring AOP中获取响应对象。如果会话无效，我想重定向到登录页面，但无法在Before advice方法中获取HttpServletResponse对象。

尝试以下方式。

    @Autowired
    private HttpServletResponse response;

    public void setResponse(HttpServletResponse response) {
        this.response = response;
    }

堆栈跟踪：

caused by: org.springframework.beans.factory.BeanCreationException: Could not autowire field: javax.servlet.http.HttpServletResponse com.****.****.aspect.LogProvider.response; nested exception is 

org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean of type [javax.servlet.http.HttpServletResponse] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {@org.springframework.beans.factory.annotation.Autowired(required=true)}
    at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:506)
    at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:87)
    at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:284)
    ... 33 more

任何帮助将不胜感激。

Answer 1

您可以通过以下方式获得回复：

RequestAttributes requestAttributes = RequestContextHolder.getRequestAttributes();
HttpServletResponse response = ((ServletRequestAttributes)requestAttributes).getResponse();

Answer 2

基本上我们从jsp页面重定向，即从UI层我们处理这种操作（重定向）。所以，我希望你将在你的应用程序中使用一些宁静的服务。对于大多数休闲服务，我们都会选择异步请求。如果它是异步和宁静服务的组合;我相信你会在你的申请中使用它。如果您的会话无效，并且您尝试访问会话＆＃39;会话＆＃39;那么它会让你陷入“IllegalStateException”＃39;对于此类情况，请遵循以下集中式“异常处理”＃39; JAX-RS提供的机制： javax.ws.rs.ext.ExceptionMapper 。请按照以下步骤操作： step-1：创建用户定义的未经检查的异常，例如MyApplicationException：

public class MyApplicationException extends RuntimeException {
  public MyApplicationException() {super();}

  // implement other methods of RuntimeException as per your requirement
}

step-2：创建用户定义类型的ExceptionMapper

public class MyApplicationExceptionHandler implements ExceptionMapper<MyApplicationException>
{
    @Override
    public Response toResponse(MyApplicationException exception)
    {
        return Response.status(Status.FORBIDDEN).entity(exception.getMessage()).build(); 
// set any Status code of 4XX as this is client side error not server side
    }
}

第3步： In all your ajax request in the UI code check this Status Code and redirect to the login page.

这就是它，你完成了更精细的实现。保证...

Answer 3

/**
 * @return the HttpServletResponse handled by the current thread
 */
public static Optional<HttpServletResponse> getThreadLocalResponse() {
    return Optional.ofNullable(RequestContextHolder.getRequestAttributes())
            .filter(ra -> ra instanceof ServletRequestAttributes)
            .map(ServletRequestAttributes.class::cast)
            .map(ServletRequestAttributes::getResponse);
}

Answer 4

要获取响应对象，您可以使用以下代码：

ServletWebRequest servletWebRequest=new ServletWebRequest(request);
HttpServletResponse response=servletWebRequest.getResponse();

获取请求对象：

HttpServletRequest request = ((ServletRequestAttributes)RequestContextHolder.currentRequestAttributes()).getR‌equest();

如果您收到null响应，那么我可以看到在返回控件时尚未形成响应。然后，唯一的方法是使用interceptors。

如何在Spring AOP中获取HttpServletRequest和HttpServletResponse对象

4 个答案: