我正在检查RetroFit的工作原理并尝试以下方法:
RestClient:
public class RestClient {
private static TaskService REST_CLIENT;
private static String ROOT =
"URL";
static {
setupRestClient();
}
private RestClient() {}
public static TaskService get() {
return REST_CLIENT;
}
private static void setupRestClient() {
OkHttpClient OkHttpClient=new OkHttpClient();
RestAdapter.Builder builder = new RestAdapter.Builder()
.setEndpoint(ROOT)
.setClient(new OkClient(new OkHttpClient()))
.setConverter(new SimpleXmlConverter());
builder.setLogLevel(RestAdapter.LogLevel.FULL);
RestAdapter restAdapter = builder.build();
REST_CLIENT = restAdapter.create(TaskService.class);
}
}
活动:
public void testMethod()
{
User user=new User("58","345435","4","","0");
RestClient.get().getWeather(user,new Callback<String>() {
@Override
public void success(String s, Response response) {
Log.d("testret", "success: " + s);
Log.d("testret", "successu: " + response.getUrl());
Log.d("testret", "successs: " + response.getStatus());
}
@Override
public void failure(RetrofitError error)
{
Log.d("testret", "errore: " + error);
Log.d("testret", "erroru: " + error.getUrl());
}
});
}
用户:
public class User {
String FTID,UUID,TYPE,DateTimeStamp,SDFVersionNb;
public User(String FTID,String UUID,String TYPE,String DateTimeStamp,String SDFVersionNb)
{
this.DateTimeStamp=DateTimeStamp;
this.FTID=FTID;
this.UUID=UUID;
this.SDFVersionNb=SDFVersionNb;
this.TYPE=TYPE;
}
}
界面:
public interface TaskService {
@POST("/GetBulkQueryUpdates")
void getWeather(@Body User user,
Callback<String> callback);
}
上面的webservice方法返回以下内容:
<ROWS>
<ROW>
<GroupBy>3</GroupBy>
<QUERY>
Query Statement
</QUERY>
</ROW>
</ROWS>
所以我使用post方法来检索上面的数据,但是我每次都在获取内部服务器错误500,但是当从web执行webservice方法时,正在检索数据。所以问题是上面的代码,但我无法弄清楚是什么。我尝试添加.setConverter(new SimpleXmlConverter());看了以下网址后: Android Retrofit return status 500 internal server error 但它是一样的。
任何帮助将不胜感激。
答案 0 :(得分:0)
试试这个......添加.xml
将解决问题
public interface TaskService {
@POST("/GetBulkQueryUpdates.xml")
void getWeather(@Body User user,
Callback<String> callback);
}
你的User
类必须采用这种格式
@Root(name = "breakfast_menu")
public class BreakFastMenu
{
@ElementList(inline = true)
List<Food> foodList;
}
@Root(name="food")
public class Food
{
@Element(name = "name")
String name;
@Element(name = "price")
String price;
@Element(name = "description")
String description;
@Element(name = "calories")
String calories;
}
编辑1:
@Root
是一个注释,在个案中它应该是@Root(name = "ROWS")
,这是你的XML的根元素