Question

我有一张表格来标记员工＆＃39;人力资源部门填写的每个现有员工的出勤情况。我需要它来显示数据库中标记出勤的当前值，否则它应该是空白的。

在我的控制器中，我查询现有结果：

$results = Attendance::where('Sdate', '=', date("Y-m-d", strtotime($TheDate))) ->get();

然后循环访问它们以获取员工详细信息：

foreach($results as $result)
{
    $contractors = DB::table('contractors') ->where('contractors.AreaPosition', '=', $department) ->where('PRN', '!=', $result->PRN) ->get(); $employees = DB::table('current_employees') ->where('current_employees.AreaPosition', '=', $department) ->where('PRN', '!=', $result->PRN) ->get(); $showEmployees = array_merge($contractors, $employees);
}

这应该排除所有在该日期保存了记录的员工，但它似乎没有正确循环。它将排除一些结果，但不是全部。如果我返回结果变量，我会得到正确的记录列表，所以我知道该部分工作正常。

我希望在我看来实现的目标是：

@foreach($attendance as $results)

Show form where there's an existing record for this date and department

@endforeach



@foreach($employees as $employee)

Show form for all employees in this department (but should exclude results where there is a record in attendance)

@endforeach

Answer 1

您的代码存在的问题是您将结果保存在变量中而不是数组中。您的解决方案是将数据存储在数组中

foreach($results as $result)
{
    $contractors[] = DB::table('contractors') ->where('contractors.AreaPosition', '=', $department) ->where('PRN', '!=', $result->PRN) ->get(); $employees = DB::table('current_employees') ->where('current_employees.AreaPosition', '=', $department) ->where('PRN', '!=', $result->PRN) ->get(); $showEmployees = array_merge($contractors, $employees);
}

尝试打印承包商阵列，看看会发生什么。我希望这有效

Answer 2

Laracasts对我的回答。

我需要做的是创建一个要检查的变量列表（员工编号）

    $PRNs = Attendance::where('Sdate', '=', date("Y-m-d", strtotime($TheDate)))->lists('PRN');

然后使用Laravel的whereNotIn，检查列表。

    $contractors = DB::table('contractors')
        ->where('contractors.AreaPosition', '=', $department)
        ->whereNotIn('PRN', $PRNs)
        ->get();

Foreach循环未正确通过

2 个答案: