Question

我有一个sql表，如下所示：

+------+------------+---------+---------------------+-----------+
| SrNo | BidderName | BidAmt  |       BidDate       | BidTicks  |
+------+------------+---------+---------------------+-----------+
|    1 | ARBAAZ     | 500.00  | Apr 30 2015 10:27AM | 348854000 |
|    2 | SHEKHAR    | 600.00  | Apr 30 2015 10:28AM | 348845000 |
|    3 | SHEKHAR    | 800.00  | Apr 30 2015 10:28AM | 348838000 |
+------+------------+---------+---------------------+-----------+

我将这个以JSON格式发送给我的客户端。

我可以通过以下方式获取值：

var data;

Table.forEach(function (field) {
    var name = field.BidderName;
    var amount = field.BidAmt;
    data = "";
});

我正在尝试使用Table为我的flot图创建一个看起来像这样的对象：

var dataset = [
    {
        label: "ARBAAZ",
        data: [[348854000, 500.00]],//created from [bidticks,bidamt]
        color: "#FF0000",
        points: { fillColor: "#FF0000", show: true },
        lines: { show: true }
    },
    {
        label: "SHEKHAR",
        data: [[348845000, 600.00], [48838000, 800.00]],
        color: "#0062E3",
        points: { fillColor: "#0062E3", show: true },
        lines: { show: true }
    }
];

任何想法，我怎么能做到这一点？

Answer 1

我不知道你在json对象中有什么确切的数据结构。但是，我认为你可以这样做

padding : 15px

现在您可以在数据集对象中使用teamRed和teamBlue。

我假设您确实拥有此BidderName，以区分此行属于蓝队或红队。

Answer 2

假设你的json数据是var'data'，你可以使用filter函数

进行循环

  var seen = {};
    data = data.filter(function(entry) {
        var previous;

        // Have we seen this label before?
        if (seen.hasOwnProperty(entry.label)) {
            // Yes, grab it and add this data to it
            previous = seen[entry.label];
            var data = [entry.BidTicks, entry.BidAmt] ;
            previous.data.push(data);

            // Don't keep this entry, we've merged it into the previous one
            return false;
        }    

        // entry.data probably isn't an array; make it one for consistency

        entry.data = [];
        var data = [entry.BidTicks, entry.BidAmt] ;
        entry.data.push(data);

        //delete the attributes which are not required in final output
        delete entry.BidTicks;
        delete entry.BidAmt;

        // Remember that we've seen it
        seen[entry.label] = entry;

        // Keep this one, we'll merge any others that match into it
        return true;
    });

工作小提琴就在这里 - ＆gt; fiddle to filter the array of objects

关于你的额外属性'color'，'lines'等，我相信你现在可以将它们带入最终输出。

使用条件为

2 个答案: