Question

我的桌子只有一个col，并且包含自由文本，每个关键字用空格分隔

TEXT
apple orange dog
apple banna cat

我希望得到一个像

的结果

apple 2
orange 1
dog 1
banna 1
cat 1

只用SQL吗？

Answer 1

试试这个

创建功能

Create FUNCTION [dbo].[fn_Split](@text varchar(8000), @delimiter varchar(20))
RETURNS @Strings TABLE
(   
  position int IDENTITY PRIMARY KEY,
  value varchar(8000)  
)
AS
BEGIN

DECLARE @index int
SET @index = -1

WHILE (LEN(@text) > 0)
  BEGIN 
    SET @index = CHARINDEX(@delimiter , @text) 
    IF (@index = 0) AND (LEN(@text) > 0) 
      BEGIN  
        INSERT INTO @Strings VALUES (@text)
          BREAK 
      END 
    IF (@index > 1) 
      BEGIN  
        INSERT INTO @Strings VALUES (LEFT(@text, @index - 1))  
        SET @text = RIGHT(@text, (LEN(@text) - @index)) 
      END 
    ELSE
      SET @text = RIGHT(@text, (LEN(@text) - @index))
    END
  RETURN
END

查询

 declare @ColumnNameList VARCHAR(MAX)
select @ColumnNameList  = COALESCE(@ColumnNameList +' ' ,'') +column  from table
select @ColumnNameList 
select value,count(value) as count from (select value from fn_split((select @ColumnNameList),' '))
Space_tbl group by value

MySQL，用空格分隔关键字

1 个答案: