Question

我对此很陌生，所以我坚持做一些可能非常简单的事情。

在这个程序中，我试图将每个单词从一个数组分成二维数组，以及任何句号，逗号或分号。但是，它仅在一行中重新打印该句子。我做了几个测试，似乎第一个for循环从不识别空格，逗号，句号或分号。有人可以帮忙吗？

#include <stdio.h>
#include <stdlib.h>

int main()
{
char wordProblem[1024];
char wordProblemWords[200][20];

printf("Please enter a word problem.\n");

fgets ( wordProblem, 1024, stdin );
int length = strlen (wordProblem);
int i;
int wordNumber = 0;
int letterOfWord = 0;
for ( i = 0; i < length; i++){
    if (wordProblem[i]==" ") {
        ++wordNumber;
        letterOfWord = 0;
    }else if (wordProblem[i]=="." || wordProblem[i]=="," || wordProblem[i]==";"){
        ++wordNumber;
        letterOfWord = 0;
        wordProblemWords[wordNumber][letterOfWord] = wordProblem[i];
        wordNumber;
        letterOfWord = 0;
    }else{
        wordProblemWords[wordNumber][letterOfWord] = wordProblem[i];
        ++letterOfWord;
    }
}

int j;
for (j = 0; j <= wordNumber; j++){

    printf("%s", wordProblemWords[j]);
    printf("\n");
}
return 0;
}

编辑：我已经改变了程序，问题解决了。如果你想纠正任何其他问题（我确定有吨）这里是新代码。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>//based on what user3629249 said

int main()
{
char wordProblem[1024];
char wordProblemWords[200][20];

printf("Please enter a word problem.\n");

fgets ( wordProblem, 1024, stdin );
int length = strlen (wordProblem);
int i;
int wordNumber = 0;
int letterOfWord = 0;
for ( i = 0; i <= length; i++){
    if (wordProblem[i]==' ') {          //single quotes instead of double (tivn)
        wordProblemWords[wordNumber][letterOfWord] = '\0';//added this to have a null at the end of the string, removes gibberish
        ++wordNumber;
        letterOfWord = 0;
    }else if (wordProblem[i]=='.' || wordProblem[i]==',' || wordProblem[i]==';'){
        ++wordNumber;
        letterOfWord = 0;
        wordProblemWords[wordNumber][letterOfWord] = wordProblem[i];
        wordProblemWords[wordNumber][letterOfWord] = '\0'//again to remove gibberish
    }else{
        wordProblemWords[wordNumber][letterOfWord] = wordProblem[i];
        ++letterOfWord;
    }
}

int j;
for (j = 0; j <= wordNumber; j++){

    printf("%s", wordProblemWords[j]);
    printf("\n");
}
return 0;
}

Answer 1

您需要使用单引号来比较单个字符。双引号意味着字符串。

if (wordProblem[i]==' ') {
    ++wordNumber;
    letterOfWord = 0;
} else if (wordProblem[i]=='.' || wordProblem[i]==',' || wordProblem[i]==';'){
    ...

另请注意，fgets将在结果中包含换行符。

这个程序有什么问题？单词分离程序

1 个答案: