IOS：JSONModel：NSInvalidArgumentException

Question

我有这个json数据

{"data": [{"id": 3,"nameAr": "Test","nameEn": "Test","active": 1,
"subCategories": [{"id": 27,"nameAr": "Test",
"nameEn": "Test","active": 0,
"sections": [{"id": 53,"nameAr": "Test",
"nameEn": "Test","active": 0},
{"id": 52,"nameAr": "Test","nameEn": "Test","active": 0
}]}]}],"code": "1001","message": "success"
}

解析此json时使用JSONModel https://github.com/icanzilb/JSONModel

解析此代码的代码

self.categoriesModels = [CategoryModel arrayOfModelsFromDictionaries: [results objectForKey:@"data"]];

尝试访问嵌套的json

categoryModel.subCategories

我收到了这个错误

  

- [CategoryModel subCategories]：无法识别的选择器发送到实例0x17404b910   2015-05-03 20：38：15.019 AkshefFeen [2268：786267] *由于未捕获的异常'NSInvalidArgumentException'终止应用程序，原因：' - [CategoryModel subCategories]：无法识别的选择器发送到实例0x17404b910'   * 第一次抛出调用堆栈：   （0x185fb42d8 0x1977800e4 0x185fbb3a4 0x185fb8154 0x185ebaccc 0x100027608 0x18ab1d474 0x18abd7790 0x18aa78240 0x18a9e86ec 0x185f6c2a4 0x185f69230 0x185f69610 0x185e952d4 0x18f6b36fc 0x18aa5afac 0x10002d220 0x197dfea08）   libc ++ abi.dylib：以NSException类型的未捕获异常终止

我的模特

1 - CategoryModel.h

#import "JSONModel.h"
#import "SubCategoryModel.h"

@protocol CategoryModel
@end

@interface CategoryModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;
@property (strong, nonatomic) NSArray<SubCategoryModel>* subCategories;

@end

2 - SubCategoryModel.h

@protocol SubCategoryModel
@end

@interface SubCategoryModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;
@property (strong, nonatomic) NSArray<SectionModel,Optional>* subCategories;

@end

3 - SectionModel.h

#import "JSONModel.h"

@protocol SectionModel
@end

@interface SectionModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;

@end

为什么我会收到此错误，以及如何解决？

Answer 1

@ahmed Shoeib： 可能有两个可能的原因： 1.可能是因为你的任何JSONModel类中的@synthesize关键字。

1. 这可能是由于父对象和子对象之间的命名相同。

请参阅此链接，了解JSONModel中的首选命名约定：Click here

或者您可以在此处提出同样的问题，然后您将获得正式答案或解决方案：Click Here