Question

我正在进入两天，并尝试查找输入的日期是否在特定用户之间或重叠。我似乎得到了表中不存在的EmployeeID的错误结果。

我在表格中的数据

EmployeeID  LeaveStart              LeaveEnd
         1  2015-04-14 00:00:00.000 2015-04-14 00:00:00.000
         1  2015-05-01 00:00:00.000 2015-05-02 00:00:00.000

如果我运行此查询，我会得到预期的结果，因为范围之间的日期已经在EmployeeID 1的表中

SELECT EmployeeID,LeaveStart,LeaveEnd  from EmpLeaves where (LeaveStart >= '2015-04-30' and  LeaveStart<= '2015-05-04') or (LeaveEnd between '2015-04-30' and '2015-05-04')
    and employeeid=1 

1   2015-05-01 00:00:00.000 2015-05-02 00:00:00.000

如果我为EmployeeID = 2运行相同的查询（表中不存在，我得到相同的结果），似乎是条件是返回true并忽略其余的，所以我可以把任何东西作为EmployeeID和我仍然得到相同的结果。某处我错过了什么。

SELECT EmployeeID,LeaveStart,LeaveEnd  from EmpLeaves where (LeaveStart >= '2015-04-30' and  LeaveStart<= '2015-05-04') or (LeaveEnd between '2015-04-30' and '2015-05-04')
    and employeeid=2

1   2015-05-01 00:00:00.000 2015-05-02 00:00:00.000

如果我删除了LeaveEnd中的部分，我得到了预期的结果，但是我还需要找出DateEnd字段之间是否也有日期

SELECT EmployeeID,LeaveStart,LeaveEnd  from EmpLeaves where (LeaveStart >= '2015-04-30' and  LeaveStart<= '2015-05-04') 
    and employeeid=2

Answer 1

对于您的逻辑，您需要修复where子句中的括号：

SELECT EmployeeID, LeaveStart, LeaveEnd
from EmpLeaves
where ((LeaveStart >= '2015-04-30' and  LeaveStart<= '2015-05-04') or
       (LeaveEnd between '2015-04-30' and '2015-05-04')
      ) and
      employeeid = 1

Answer 2

排序答案是你在日期周围缺少一个括号。但是，你的目标可以通过这个来实现。

SELECT EmployeeID
     , LeaveStart
     , LeaveEnd  
  FROM EmpLeaves 
 WHERE (LeaveStart <= '2015-05-04'
   OR   LeaveEnd   >= '2015-04-30')
   AND EmployeeID  = 1

查找输入的两个日期在用户

2 个答案: