Question

我想在“textEdit”中按下“enter”时尝试做某事。我正在使用onkeylistener，但它在textedit部分显示错误。我的代码是

editText.setOnKeyListener(new OnKeyListener() {
                    public boolean onKey(View view, int keyCode, KeyEvent keyevent) {
                        //When "Enter" or "Search" Pressed)
                        if ((keyevent.getAction() == KeyEvent.ACTION_DOWN) && (keyCode == KeyEvent.KEYCODE_ENTER)) {
                                EditText editText = (EditText)findViewById(R.id.editText);

                                WebView mw = (WebView) findViewById(R.id.webView2);
                                mw.setWebViewClient(new WebViewClient());
                                mw.getSettings().setJavaScriptEnabled(true);
                                mw.loadUrl("http://i.word.com/idictionary/" + editText.getText()); 
                return true;
            }
            return false;
        }
    });
}

你能帮我吗？

Answer 1

在您的代码中，“editText”变量在“if”子句中声明并初始化。以下代码应该可以正常工作：

EditText editText = (EditText)findViewById(R.id.editText);
editText.setOnKeyListener(new OnKeyListener() {
                    public boolean onKey(View view, int keyCode, KeyEvent keyevent) {
                        //When "Enter" or "Search" Pressed)
                        if ((keyevent.getAction() == KeyEvent.ACTION_DOWN) && (keyCode == KeyEvent.KEYCODE_ENTER)) { 
                                WebView mw = (WebView) findViewById(R.id.webView2);
                                mw.setWebViewClient(new WebViewClient());
                                mw.getSettings().setJavaScriptEnabled(true);
                                mw.loadUrl("http://i.word.com/idictionary/" + editText.getText()); 
                return true;
            }
            return false;
        }
    });
}

editText“无法解析符号”

1 个答案: