我想从paypal检索交易,直到找不到更多的交易。 我想在使用递归函数时这样做。 我无法弄清楚如何做到这一点。 有可能吗?
我可以进行递归,但不能聚合事务并将它们传递出函数。
为简单起见,我删除了非相关行。
this.retrieveAllTransactionsBetween = function(end_date, start_date) {
return getTransactions({
STARTDATE: Moment(start_date).format().replace('+00:00', 'Z'),
ENDDATE: Moment(end_date).format().replace('+00:00', 'Z')
})
.then(function(transactions){
if (end) { // test for end of transactions
return [];
}
console.log('finish transactions in iteration where earliest was',earliest.toDate());
return transactions.concat(retrieveAllTransactionsBetween(earliest.toDate(), start_date, customer_id));
})
.catch(function(e){
console.error('getAllTransactionsBetween general error', e);
})
;
};
this.getTransactions = function(dates) {
var stringified_api_call_param = QueryString.stringify(api_call_params);
return new Promise(function(resolve, reject) {
var sequence = Sequence.create();
sequence
.then(function (next) {
api_call_options.headers = {
'Content-Type': 'application/x-www-form-urlencoded',
'Content-Length': Buffer.byteLength(stringified_api_call_param)
}
;
var req = https.request(api_call_options, paypal_helpers.paypalCallbackWrapper(next));
req.on('error', function(e) {
return reject(e.message);
});
req.write(stringified_api_call_param);
req.end();
})
.then(function (next, res){
return resolve(res);
});
});
};
答案 0 :(得分:2)
这部分错了:
return transactions.concat(retrieveAllTransactionsBetween(earliest.toDate(), start_date, customer_id));
您希望等待进行递归调用,.concat
是一个数组函数。你应该等待它:
return retrieveAllTransactionsBetween(earliest.toDate(), start_date, customer_id).
then(function(more){ return transactions.concat(more); });