我有错误的多字符标签`\'\'-k 10 -r -n log.txt'
int
main ()
{
const char *sort[] = { "sort", "-t ' ' -k 10 -r -n log.txt", 0 };
const char *awk[] = { "awk", "{print $10}", 0 };
struct command cmd [] = { {sort}, {awk} };
return fork_pipes (2, cmd);
}
退格如何在C中转义或纠正排序参数。
所有代码:
#include <unistd.h>
struct command
{
const char **argv;
};
int
spawn_proc (int in, int out, struct command *cmd)
{
pid_t pid;
if ((pid = fork ()) == 0)
{
if (in != 0)
{
dup2 (in, 0);
close (in);
}
if (out != 1)
{
dup2 (out, 1);
close (out);
}
return execvp (cmd->argv [0], (char * const *)cmd->argv);
}
return pid;
}
int
fork_pipes (int n, struct command *cmd)
{
int i;
pid_t pid;
int in, fd [2];
/* The first process should get its input from the original file descriptor 0. */
in = 0;
/* Note the loop bound, we spawn here all, but the last stage of the pipeline. */
for (i = 0; i < n - 1; ++i)
{
pipe (fd);
/* f [1] is the write end of the pipe, we carry `in` from the prev iteration. */
spawn_proc (in, fd [1], cmd + i);
/* No need for the write and of the pipe, the child will write here. */
close (fd [1]);
/* Keep the read end of the pipe, the next child will read from there. */
in = fd [0];
}
/* Last stage of the pipeline - set stdin be the read end of the previous pipe
and output to the original file descriptor 1. */
if (in != 0)
dup2 (in, 0);
/* Execute the last stage with the current process. */
return execvp (cmd [i].argv [0], (char * const *)cmd [i].argv);
}
int
main ()
{
const char *sort[] = { "sort", "-t ' ' -k 10 -r -n log.txt", 0 };
const char *awk[] = { "awk", "{print $10}", 0 };
struct command cmd [] = { {sort}, {awk} };
return fork_pipes (2, cmd);
}
答案 0 :(得分:0)
我假设字符串作为参数传递给exec
函数之一?那么你不能将多个参数放在一个字符串中,因为exec
会把它作为程序的一个参数。
exec
的参数成为被调用程序中的argv
数组,因此例如"-t ' ' -k 10 -r -n log.txt"
将成为单参数(例如{{ 1}})在被调用的程序中。你需要分开参数:
argv[1]