Question

我的问题是当我尝试在我的字符串上使用exec时，控制台会抛出此错误：

Uncaught TypeError: Cannot read property '1' of null

这是我的代码：

var regexes = {
    "bold": [/\[bold\](.*)\[\/bold\]/g,"<b>","</b>"],
    /*"italics": [[/\[italics\]/g,"<i>"],[/\[\/italics\]/g,"</i>"]],
    "underline": [[/\[underline\]/g,"<u>"],[/\[\/underline\]/g,"</u>"]],
    "spoiler": [[/\[spoiler\]/g,"<div class='spoilerEnhanced'>"],[/\[\/spoiler\]/g,"</div>"]],
    "strikethrough": [[/\[strikethrough\]/g,"<del>"],[/\[\/strikethrough\]/g,"</del>"]],*/
}
var functioners = {
    "zalgo": [/(\[zalgo\].*\[\/zalgo\])/g],
    "flip": [/(\[flip\].*\[\/flip\])/g],
    "superscript": /[a-zA-Z0-9]\^([a-zA-Z0-9]*)/g,
    "triforce": /(%triforce)/g,
    "list": /(^\*\ .*)/g
}

var replies = document.getElementsByClassName("postMessage");
var x = 0
function memes(x,z) {
    window.setTimeout(function() {
        var theNew = "";
        theNew = replies[x].innerHTML;
        for (key in regexes) {
            if (regexes[key][0].exec(replies[x].innerHTML) !== null) {
                theNew = regexes[key][1] + regexes[key][0].exec(replies[x].innerHTML)[1] + regexes[key][2];
            }
        }
        if (x < z) {
            memes(x+1,z);
        }
    },5);
}
memes(x,replies.length-1);

这段代码应该通过类名＆＃34; postMessage＆＃34;然而，用exec替换某些文本。抛出错误。类似的问题在RegExp.exec() returns NULL sporadically结束。我无法解决如何在目前的情况下做到这一点。如果有人可以帮我解决这个问题，那就太棒了。 请注意：此代码位于Google Chrome扩展脚本中!!

Answer 1

请你试试如下：

for (key in regexes) {
        var m = regexes[key][0].exec(replies[x].innerHTML);
        if (m !== null) {
            theNew = regexes[key][1] + m[1] + regexes[key][2];
       }
}

请让我知道

Javascript exec返回null

1 个答案: