Question

来自apple docs

根据文档

    func vvlog10f(_ _: UnsafeMutablePointer<Float>,
                _ _: UnsafePointer<Float>,
                _ _: UnsafePointer<Int32>)
 /* y */ /* x */ /* n */

那么我做错了什么？

这是我的代码

import Accelerate

var input:[Float] = [0.124,0.5,0.0056]
var output:[Float] = []
var i:Int32 = Int32(input.count)
vvlog10f(&output,&input,&i)

println("output is \(output)")

输出为[]

Answer 1

来自Apple's Swift Blog的示例：

   import Accelerate

   let a: [Float] = [1, 2, 3, 4]
   let b: [Float] = [0.5, 0.25, 0.125, 0.0625]
   var result: [Float] = [0, 0, 0, 0]

   vDSP_vadd(a, 1, b, 1, &result, 1, 4)

所以看起来你只需要＆amp;对于可变指针。

Answer 2

这是最终适用于此示例的内容

import Accelerate

var input:[Float] = [0.124,0.5,0.0006]
var output:[Float] = [Float](count: input.count, repeatedValue: 0.0)
var temp:Int32 = Int32(input.count)
var i:[Int32] = [temp]
vvlog10f(&output,input,i)

println("output is \(output)")

在Swift中使用Accelerate框架

2 个答案: