Question

这里我有一些示例代码从Webservice获得响应。我给出了这样的输入：

String values = Bham.getBDetails("xxxxxxxxx");

这里的肥皂用户界面响应看起来像：

           <GetxxxxxhDetailsResponse >
         <GetxxxxxhDetailsResult><![CDATA[<xxxxxFAMILY>
          <FAMILYDETAIL>
               <xxxx_ID>11111</2_ID>
               <ID>50218036</ID>
               <NAME>???? ????</NAME>
              <FATHERNAME>????????</FATHERNAME>
          </FAMILYDETAIL>
          <FAMILYDETAIL>
                <xxxx_ID>2222</2222_ID>
                <ID>91622649</ID>
               <NAME>????</NAME>
              <FATHERNAME>?????</FATHERNAME>
             </FAMILYDETAIL>
            </xxxxxHFAMILY>]]>
      </GetxxxxxhDetailsResult>
      </GetxxxxxhDetailsResponse>

响应CDATA就是这样，我正在我的控制台中这样出来：

           <xxxxFAMILY>
               <FAMILYDETAIL>
             <xxxxx_ID>9999-PXFR-00159</xxxxx_ID>
            <ID>50218036</ID>
           <NAME>???? ????</NAME>
          <FATHERNAME>????????</FATHERNAME>
         <DOB>01/01/1984</DOB>
         <GENDER>?????</GENDER>
       <MARITALSTATUS>???????</MARITALSTATUS>
     <MOTHERNAME>????</MOTHERNAME>
    <RELATIONSHIPWITHHOF>?????</RELATIONSHIPWITHHOF>
    <SPOUSENAME>?????</SPOUSENAME>
   </FAMILYDETAIL>
    <FAMILYDETAIL>
        <xxxxx_ID>9999-PXFR-00159</xxxxx_ID>
          <ID>91622649</ID>
       <NAME>????</NAME>
      <FATHERNAME>?????</FATHERNAME>
     <DOB>01/01/2007</DOB>
     <GENDER>?????</GENDER>
    <MARITALSTATUS>????????</MARITALSTATUS>
      <MOTHERNAME>????</MOTHERNAME>
    <RELATIONSHIPWITHHOF>??????</RELATIONSHIPWITHHOF>
    <SPOUSENAME />
   </FAMILYDETAIL>
  </xxxxxFAMILY>

所以在这里我想得到xxxx_ID，ID所有属性。你能建议我吗？

Answer 1

将XML读入文档，并使用Xpath或文档导航来获取您所追求的节点值。

Viral Patel有一个关于xpath和java的教程，但还有很多其他的。

http://viralpatel.net/blogs/java-xml-xpath-tutorial-parse-xml/

从您发布的小内容中，您需要从详细信息实体中读取字符串并从中构建XML文档。阅读我发布的博客或此回复How to create a XML object from String in Java?

这应该让你去。

public static List<String> getIdFromXml(String xml) {
    Document xmlDoc = loadXML(xml);
    NodeList nodeList = xmlDoc.getElementsByTagName("ID");
    List<String>ids = new ArrayList<String>(nodeList.getLength());
    for(int i=0;i<nodeList.getLength(); i++) {
        Node x = nodeList.item(i);
        ids.add(x.getNodeValue());
    }

    return ids;
}

public static Document loadXML(String xml) throws Exception
{
    DocumentBuilderFactory fctr = DocumentBuilderFactory.newInstance();
    DocumentBuilder bldr = fctr.newDocumentBuilder();
    InputSource insrc = new InputSource(new StringReader(xml));
    return bldr.parse(insrc);
}

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1 个答案: