Question

我有以下一段servlet代码（在Apache Tomcat v7.0上运行），试图从jsp页面获取用户输入，然后尝试AES加密它（在我的类AES_BC中使用充气城堡实现）。我正在实例化我的AES_BC类，只是为了在方法myname（）中进行测试。服务器很好，我可以提供一些输入，但是当在doGet中调用myname（）时，我得到一个运行时异常。代码和例外情况如下：

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;


import java.io.IOException;
import java.io.PrintWriter;
import java.text.SimpleDateFormat;
import java.util.Date;
import aes_bc.AES_BC;

@WebServlet(name = "EncryptServlet", urlPatterns = {"/Encrypt"})
public class EncryptServlet extends HttpServlet {
  private static final long serialVersionUID = 1L;
  protected void doGet(HttpServletRequest request, 
      HttpServletResponse response) throws ServletException, IOException 
  {
    // reading the user input
    String query= request.getParameter("color");   
    String color = "blue";
    PrintWriter out = response.getWriter();



    myname();
    System.out.println("color:"+color);
    System.out.println("user query:"+query);

    byte [] in_bytes = query.getBytes();

    String tsMsg = query + new SimpleDateFormat("yyyyMMddhhmm").format(new Date());
    System.out.println("time stamped message:"+tsMsg+"\n");

    out.println (
      "<!DOCTYPE html PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\"" + "http://www.w3.org/TR/html4/loose.dtd\">\n" +
      "<html> \n" +
        "<head> \n" +
          "<meta http-equiv=\"Content-Type\" content=\"text/html; charset=UTF-8\"> \n" +
          "<title> Bouncy Castle Encryption/Crypto JS decryption </title> \n" +
        "</head> \n" +
        "<body> \n" +
          "<font size=\"9px\" color=\"" + color + "\">" +
            "Plain text query:" + query +
          "</font> \n" +
          "<li>" + "Timestamped query:" + tsMsg +
          "</li> \n" +
        "</body> \n" +
      "</html>" 
    );  

  } 

  public void myname(){

      byte[] enc_key = "0123456789abcdefghijklmn".getBytes();
      AES_BC aesencrypt = new AES_BC(enc_key);
      String msg1 = "test msg";
      byte [] in_bytes = msg1.getBytes();

      System.out.println("message:"+msg1);
      }
    }

例外情况如下：

javax.servlet.ServletException: Servlet execution threw an exception

root cause

java.lang.NoClassDefFoundError: org/bouncycastle/crypto/BlockCipher
    EncryptServlet.myname(EncryptServlet.java:59)
    EncryptServlet.doGet(EncryptServlet.java:26)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:620)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:727)

root cause

java.lang.ClassNotFoundException: org.bouncycastle.crypto.BlockCipher
    org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1720)
    org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1571)
    EncryptServlet.myname(EncryptServlet.java:59)
    EncryptServlet.doGet(EncryptServlet.java:26)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:620)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:727)

当我将一个main方法添加到我的AES_BC类并独立测试时，它可以正常工作。我一直在摸索着弄清楚如何解决这个问题。任何帮助将不胜感激。

Answer 1

您的异常非常明显：

java.lang.ClassNotFoundException: org.bouncycastle.crypto.BlockCipher

你的类路径中没有必要的jar，如果你正在使用maven，只需在compile范围内添加一个依赖项，或者在互联网上找到丢失的jar并将其添加到你的{{1文件夹。

Answer 2

下载此页面中提到的jar文件，把它放在你的/ Tomcat / webapps / YourApp / WEB-INF / lib中，我认为你的问题会解决，你不会有这个异常http://www.java2s.com/Code/Jar/l/Downloadlcryptojdk16143jar.htm

使用jsp servlet和bouncy castle运行时异常

2 个答案: