Question

我的搜索逻辑存在问题。当用户想要搜索区域＆＃34;团队区域123＆＃34;它会因空间而搜索姓氏。只是想看看我们怎么能告诉搜索它不是第一个姓氏搜索而你做错了？

public IEnumerable<User> Query()
{
    if (!String.IsNullOrEmpty(query))
    {
        int ext = 0;
        if (query.Contains("."))
        {
            return repository.SelectSearchByEmail(query.Trim());
        }
        else if (query.Contains(","))
        {
            var names = query.Split(',');
            var firstName  = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (query.Contains(" "))
        {
            var names = query.Split(' ');
            var firstName = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (query.Contains("_"))
        {
            var names = query.Split('_');
            var firstName = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (int.TryParse(query, out ext))
        {
            return repository.SelectSearchByExt(ext);
        }
        else
        {
            return repository.SelectAllUserByQuery(query);
        }
    }
    return new List<User>();
}

Answer 1

尝试这样的事情：

计算字符串中的空格数

// For brevity use.
int spacesCount = query.Count(f => f == ' ');

// For speed use.
int spacesCount = 0;

foreach (char c in query) 
{
    if (c == ' ')
    {
        count++;
    }
}

只有当有1个空格时才会落入其他地方，例如“名字姓氏”

所以改变

else if (query.Contains(" "))

到

else if (spacesCount == 1)

您的代码应如下所示：

public IEnumerable<User> Query()
{
    if (!String.IsNullOrEmpty(query))
    {
        int ext = 0;
        int spacesCount = query.Count(f => f == ' ');

        if (query.Contains("."))
        {
            return repository.SelectSearchByEmail(query.Trim());
        }
        else if (query.Contains(","))
        {
            var names = query.Split(',');
            var firstName  = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (spacesCount == 1)
        {
            var names = query.Split(' ');
            var firstName = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (query.Contains("_"))
        {
            var names = query.Split('_');
            var firstName = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (int.TryParse(query, out ext))
        {
            return repository.SelectSearchByExt(ext);
        }
        else
        {
            return repository.SelectAllUserByQuery(query);
        }
    }
    return new List<User>();
}

Answer 2

检查空格时缺少一个条件：

public IEnumerable<User> Query()
{
    if (!String.IsNullOrEmpty(query))
    {
        int ext = 0;
        if (query.Contains("."))
        {
            return repository.SelectSearchByEmail(query.Trim());
        }
        else if (query.Contains(","))
        {
            var names = query.Split(',');
            var firstName  = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (query.Contains(" ") && query.Split(" ").Length ==2 ) //This Line
        {
            var names = query.Split(' ');
            var firstName = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (query.Contains("_"))
        {
            var names = query.Split('_');
            var firstName = names[0];
            var lastName = names[1];
            return repository.SelectSearchByFirstAndLastName(firstName, lastName);
        }
        else if (int.TryParse(query, out ext))
        {
            return repository.SelectSearchByExt(ext);
        }
        else
        {
            return repository.SelectAllUserByQuery(query);
        }
    }
    return new List<User>();
}

Answer 3

如果我理解您的问题，那么您可以执行以下操作：

HasOptional(d => d.Car)
    .WithOptionalDependent()
    .Map(d => d.MapKey("CarId"));

搜索逻辑正在做错搜索？

3 个答案: