Question

经过一些研究后，我能够通过网络设备从RESTful API获取数据：

if sys.version_info >= (2,7,9):
    import ssl
    conn = httplib.HTTPSConnection('192.168.158.136', 443, context=ssl._create_unverified_context())
else:
    conn = httplib.HTTPSConnection('192.168.158.136', 443)

headers = {"Authorization"  : "Basic %s" % base64.b64encode('user:pass'),
           "Content-Type"   : "application/json"}

url="https://192.168.158.136/wapi/v1.2/network?_return_fields%2b=extattrs"

conn.request('GET', url, headers=headers)
response = conn.getresponse()

print response.read()
conn.close()

这会打印出我需要的对象的json格式列表：

[
    {
        "_ref": "network/ZG5zLm5ldHdvcmskMTAuMC4wLjAvMjQvMA:10.0.0.0/24/default", 
        "extattrs": {
            "Location": {
                "value": "NAU"
            }
        }, 
        "network": "10.0.0.0/24", 
        "network_view": "default"
    }, 
    {
        "_ref": "network/ZG5zLm5ldHdvcmskMTAuMS4xLjAvMjQvMA:10.1.1.0/24/default", 
        "extattrs": {
            "Location": {
                "value": "BTN"
            }
        }, 
        "network": "10.1.1.0/24", 
        "network_view": "default"
    }, 
    {
        "_ref": "network/ZG5zLm5ldHdvcmskMTAuMi4yLjAvMjQvMA:10.2.2.0/24/default", 
        "extattrs": {
            "Location": {
                "value": "TRT"
            }
        }, 
        "network": "10.2.2.0/24", 
        "network_view": "default"
    }, 
    {
        "_ref": "network/ZG5zLm5ldHdvcmskMTkyLjE2OC4wLjAvMTYvMA:192.168.0.0/16/default", 
        "extattrs": {
            "Location": {
                "value": "MCW"
            }
        }, 
        "network": "192.168.0.0/16", 
        "network_view": "default"
    }
]

现在我需要＆＃34;不知何故＆＃34;将其格式化为仅包含＆＃34; network＆＃34;以及extattrs＆＃34;位置＆＃34;的内容（并且只有位置，还有其他人，但我只需要位置），格式为：

网络位置，即

10.0.0.0/24 NAU
10.1.1.0/24 BTN
10.2.2.0/24 TRT
192.168.0.0/16 MCW

我努力完成这项工作，即重新格式化我从查询中获取的JSON代码。

Answer 1

您只需使用json模块将JSON数组解析为dict。

import json

# Your code here

net_loc = []
resp_d = json.loads(response.read())
for obj in resp_d:
    net_loc.append(obj["network"] + " " + obj["extattrs"]["Location"]["value"])

net_loc列表将包含您想要的内容。

Answer 2

发布map方法风险很大，因为人们似乎不喜欢map，但我会尝试一下：

if sys.version_info >= (2,7,9):
    import ssl
    conn = httplib.HTTPSConnection('192.168.158.136', 443, context=ssl._create_unverified_context())
else:
    conn = httplib.HTTPSConnection('192.168.158.136', 443)

import json
headers = {"Authorization"  : "Basic %s" % base64.b64encode('user:pass'),
           "Content-Type"   : "application/json"}

url="https://192.168.158.136/wapi/v1.2/network?_return_fields%2b=extattrs"

conn.request('GET', url, headers=headers)
response = conn.getresponse()

data = json.loads(response.read())
conn.close()

#variant 1. "map" approach
networks = map(lambda x: "%s %s" % (x["network"], x["extattrs"]["Location"]["value"]), data)

print("\n".join(networks))

#variant 2. "for" approach
networks = []
for item in data:
  networks.append("%s %s" % (item["network"], item["extattrs"]["Location"])["value"]))

print("\n".join(networks))

形成httplib响应（json）

2 个答案: