Question

我创建了一个python包，即 package_demo ，它有三个python模块 init .py ， employee.py 和 manager.py 。

employee.py： -

def topSalary_employee(salary_list):
    return max(salary_list);

def leastSalary_employee(salary_list):
    return min(salary_list);

def avarageSalary_employee(salary_list):
    summation=0;
    for salary in salary_list:
        summation+=salary;
    return summation;

manager.py： -

def topSalary_manager(salary_list):
    return max(salary_list);

def leastSalary_manager(salary_list):
    return min(salary_list);

def avarageSalary_manager(salary_list):
    summation=0;
    for salary in salary_list:
        summation+=salary;
    return summation;

初始化的.py： -

from manager import*;
from employee import*;

现在我想访问 manager.py 和 employee.py 的所有功能到另一个python模块，即 AAA.py ，这是位于包 package_demo 之外。这是AAA.py的代码

AAA.py： -

import package_demo

employee_salary_list = [12000,23000,18000,25000,8000,17000];
manager_salary_list = [32000,45000,28000,50000,38000,44000];

print("\t...Manager Salary Details...");
print("Highest salary of Manager : ",package_demo.topSalary_employee(manager_salary_list));
print("Lowest salary of Manager : ",package_demo.leastSalary_manager(manager_salary_list));
print("Average salary of Manager : ",package_demo.avarageSalary_manager(manager_salary_list));

print("\t...Employee Salary Details...");
print("Highest salary of Employee : ",package_demo.topSalary_employee(employee_salary_list));
print("Lowest salary of Employee : ",package_demo.leastSalary_employee(employee_salary_list));
print("Average salary of Employee : ",package_demo.avarageSalary_employee(employee_salary_list));

但是当我运行AAA.py程序时，它会显示一些错误，如下面的

Traceback (most recent call last):
  File "F:\Document\Files\Coding\Java Eclipse\Python Project\First Project\src\AAA.py", line 1, in <module>
    import package_demo
  File "F:\Document\Files\Coding\Java Eclipse\Python Project\First Project\src\package_demo\__init__.py", line 1, in <module>
    from manager import*;
ImportError: No module named 'manager'

Answer 1

所有导入都是从您启动Python的目录中进行评估的，因此当init.py尝试导入管理器时，Python将尝试从您当前所在的目录中查找，而不是从init.py所在的目录中查找。 / p>

您要使用相对导入或将导入转换为绝对导入：

相对

from .manager import*;
from .employee import*;

绝对值：

from package_demo.manager import*;
from package_demo.employee import*;

将python包导入python模块时的ImportError

1 个答案: