Question

我想在控制器中显示图像。它现在显示图像。这是我试图做的。 1-硬编码相对图像路径，以便不会混淆图像 2-我把这段代码放在构造函数中，它在＆＃34; parent::__construct();＆＃34;之前工作。线。但是在这一行之后它没有显示出来。

class Fileupload extends Frontend_Controller
{
    function __construct()
    {
        //code is working here and showing image

        parent::__construct();

        //code below this line is not working

        $this->load->model('front_end/user_model');
        $dst_path = "C:\\xampp\htdocs\myweb\assets/uploads/avatar.jpg";
        header('Content-Type: image/jpeg');
        header('Content-Length: ' . filesize($dst_path));
        readfile($dst_path,true);
        die;
    }

任何建议??

Answer 1

像这样编写代码

<?php 
class Fileupload extends Frontend_Controller
{
  function __construct()
  {
      parent::__construct();
   }


 public function index() {
      $this->load->model('front_end/user_model');

      $dst_path   =   "C:\\xampp\htdocs\myweb\assets/uploads/avatar.jpg";

      header('Content-Type: image/jpeg');

      header('Content-Length: '  .  filesize($dst_path));

      readfile($dst_path,true);

   } 
}

＆GT？; 在任何MVC框架中，默认情况下始终调用索引函数。这应该有所帮助。试着告诉

Answer 2

请试试这个：

select 
    t.noEmploye, 
    t.NoProjet, 
    c.count
from temps t
    inner join (select noProjet, noEtape, count(*) as count from temps group by noProjet, noEtape) as c 
        on t.noProjet = c.noProjet
order by noEmploye

或者，请阅读this了解更多示例。：）

为什么Codeigniter读取文件不起作用？

2 个答案: