我想在退房日期的入住日期后1天分配..并在结账日期隐藏所选日期和入住日期日期选择日期之前的日期..
<table>
<tr>
<td>
<br>Check in date
<td width="10">
<br>:
</td>
<td>
<br>
<input type = "date" name= "datein" placeholder="yyyy-mm-dd" id="datepicker1" class="date"/>
</td>
<script>
$( "#datepicker1" ).datepicker({
minDate: 0,
dateFormat: "yy-mm-dd",
maxDate: '+30D',
});
</script>
</td>
</tr>
<tr>
<td>
<br>Check out date
<td width="10">
<br>:
</td>
<td>
<br>
<input type = "date" name= "dateout" placeholder="yyyy-mm-dd" id="datepicker2" class="date"/>
</td>
<script>
$( "#datepicker2" ).datepicker({
minDate: 0,
dateFormat: "yy-mm-dd",
maxDate: '+30D'
});
</script>
</td>
</tr>
</table>
答案 0 :(得分:1)
对不起,我错过了一部分。我的答案已修改,请参阅this
我在here上使用了同样的内容,如下所示
$( "#datepicker1" ).datepicker({
defaultDate: +1,
dateFormat: 'dd/mm/yy',
beforeShow: function(input, inst) {
//datepopupdirection(input, inst); - ignore this line
},
minDate: new Date(),
onSelect: function(dateText, inst) {
if($('#datepicker2').val() == '') {
var current_date = $.datepicker.parseDate('dd/mm/yy', dateText);
current_date.setDate(current_date.getDate()+1);
$('#datepicker2').datepicker('setDate', current_date);
}
},
onClose: function(selectedDate, test) {
if(selectedDate != ""){
var $date = new Date($( "#datepicker1" ).datepicker( "getDate" ));
$date.setDate($date.getDate()+1);
$( "#datepicker2" ).datepicker( "option", "minDate", $date );
$( "#datepicker2" ).datepicker('setDate', $date);
/* set the max date range 2months */
var $minusDate = new Date($( "#datepicker1" ).datepicker( "getDate" ));
$minusDate.setDate($minusDate.getDate()-1);
var maxDate = new Date($minusDate);
maxDate.setMonth(maxDate.getMonth()+ 2);
$( "#datepicker2" ).datepicker( "option", "maxDate", maxDate );
}
}});
$( "#datepicker2" ).datepicker({
dateFormat: 'dd/mm/yy',
beforeShow: function(input, inst) {
//insertArrow();
//datepopupdirection(input, inst);
},
minDate: new Date(),
onClose: function( selectedDate ) {
if(selectedDate != ""){
/*$( "#H-startDate" ).datepicker( "option", "maxDate", selectedDate );*/
}
}
});
希望这有帮助!!如果您需要更多说明,请告诉我
答案 1 :(得分:0)
我已根据我的姓名日期选择器更改日期选择器名称
$( "#datepicker1" ).datepicker({
defaultDate: +1,
dateFormat: 'dd/mm/yy',
beforeShow: function(input, inst) {
//datepopupdirection(input, inst); - ignore this line
},
minDate: new Date(),
onSelect: function(dateText, inst) {
if($('#datepicker2').val() == '') {
var current_date = $.datepicker.parseDate('dd/mm/yy', dateText);
current_date.setDate(current_date.getDate()+1);
$('#datepicker2').datepicker('setDate', current_date);
}
},
onClose: function(selectedDate, test) {
if(selectedDate != ""){
var $date = new Date($( "#datepicker1" ).datepicker( "getDate" ));
$date.setDate($date.getDate()+1);
$( "#datepicker2" ).datepicker( "option", "minDate", $date );
$( "#datepicker2" ).datepicker('setDate', $date);
/* set the max date range 2months */
var $minusDate = new Date($( "#datepicker1" ).datepicker( "getDate" ));
$minusDate.setDate($minusDate.getDate()-1);
var maxDate = new Date($minusDate);
maxDate.setMonth(maxDate.getMonth()+ 2);
$( "#datepicker2" ).datepicker( "option", "maxDate", maxDate );
}
}
});
答案 2 :(得分:0)
您可以使用此功能实现。
演示
$("#datepicker1").datepicker({
minDate: 0,
dateFormat: "yy-mm-dd",
maxDate: '+30D',
onSelect: function() {
var date = new Date($(this).val());
var ret = new Date(date.setDate(date.getDate() + 1));
var year = ret.getFullYear(), month = (ret.getMonth() + 1), day = ret.getDate();
$("#datepicker2").val(year+"-"+month+"-"+day);
}
});
<link href="http://code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css" rel="stylesheet"/>
<script src="http://code.jquery.com/jquery-1.10.2.js"></script>
<script src="http://code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
<input type="text" id="datepicker1" />
<input type="text" id="datepicker2" />