MySQL:从子查询结果更新表列

时间:2010-06-08 08:20:39

标签: mysql sql-update

在Members表上有“MemberID”和“PointsEarned”列。

我想从此查询的结果更新PointsEarned列:

SELECT m.MemberID, m.UserName, 
     ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + 
     ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) +
     ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 )
     as PointsEarned
   FROM Members as m

有人可以通过一个查询告诉我应该怎么做吗?

谢谢!

1 个答案:

答案 0 :(得分:6)

您可能需要尝试以下操作:

UPDATE   Members m
SET      PointsEarned = 
     ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + 
     ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) +
     ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 );

测试用例:

CREATE TABLE Members (MemberId int, PointsEarned int);
CREATE TABLE EventsLog (MemberID int, EventsTypeID int);
CREATE TABLE ChatMessages (MemberID int);

INSERT INTO Members VALUES (1, 0);
INSERT INTO Members VALUES (2, 0);
INSERT INTO Members VALUES (3, 0);

INSERT INTO EventsLog VALUES (1, 2);
INSERT INTO EventsLog VALUES (1, 2);
INSERT INTO EventsLog VALUES (1, 3);
INSERT INTO EventsLog VALUES (2, 2);
INSERT INTO EventsLog VALUES (3, 3);

INSERT INTO ChatMessages VALUES (1);
INSERT INTO ChatMessages VALUES (1);
INSERT INTO ChatMessages VALUES (2);

结果:

SELECT * FROM Members;
+----------+--------------+
| MemberId | PointsEarned |
+----------+--------------+
|        1 |           23 |
|        2 |           10 |
|        3 |            3 |
+----------+--------------+
3 rows in set (0.00 sec)