Question

我的目标是使用正则表达式查找单词列表中的所有匹配项。我得到了它的工作，但我希望能够指定多个字母，并且每个字母只出现它指定的次数。

我的代码：

import re
with open('wordlist.txt') as f:
    content = f.readlines()

def search(regex):
    pattern=re.compile(regex)
    for word in content:
        word=word.strip()
        if(pattern.findall(word)):
            print(word)

示例：

search(r'^(b|e|a|c|h|e|s|q|r){7}$') match only words with 7 of those 9 letters. only letters in the word can be those 9. In this case beaches would be returned
search(r'^(f|o|o|c|l|t){4}$') match only words with 4 of those 6 letters. only letters in the word can be those 6. In this case foot and fool and colt would be returned
search(r'^(f|o|d|c|l|t){4}$') match only words with 4 of those 6 letters. only letters in the word can be those 6. In this case only colt would be returned

Answer 1

我不认为正则表达式是去这里的方式。你不关心订单，只关心每封信的数量。这听起来像是一个数组或dict的工作。

如何将参数设为search dict，其中键是每个字母，值是允许出现该字母的次数？然后只需深度复制dict，遍历字符串，然后递减。如果找不到密钥，或者密钥已经为0，则会失败并转到下一个字符串。

正则表达式基于列表的单个字母或多个帐户

1 个答案: