填充日期时间列

时间:2015-04-29 13:57:59

标签: sql sql-server tsql ssms

我想在存储过程中动态填充日期时间列。下面是我目前所拥有的查询,但会降低查询性能。

CREATE TABLE #TaxVal
(
    ID         INT
    , PaidDate DATETIME
    , CustID   INT
    , CompID   INT 
)

INSERT INTO #TaxVal(ID, PaidDate, CustID, CompID)
VALUES(01, '20150201',12, 100)
    , (03,'20150301', 18,101)
    , (10,'20150401',19,22)
    , (17,'20150401',02,11)
    , (11,'20150411',18,201)
    , (78,'20150421',18,299)
    , (133,'20150407',18,101)

--  SELECT * FROM #TaxVal

DECLARE @StartDate DATETIME = '20150101'
    , @EndDate     DATETIME = '20150501'

DECLARE @Tab TABLE 
(
    CompID    INT
    , DateField DATETIME
)

DECLARE @T INT
SET @T = 0
WHILE @EndDate >= @StartDate + @T 
BEGIN
    INSERT INTO @Tab 
    SELECT CompID
         , @StartDate + @T AS DateField
    FROM #TaxVal
    WHERE CustID = 18
        AND CompID = 101
    ORDER BY DateField DESC

    SET @T = @T + 1
END

SELECT DISTINCT * FROM @Tab 

DROP TABLE #TaxVal

编写此查询以获得更好性能的最佳方法是什么?

2 个答案:

答案 0 :(得分:1)

改变这个:

DECLARE @T INT
SET @T = 0
WHILE @EndDate >= @StartDate + @T 
BEGIN
    INSERT INTO @Tab 
SELECT CompID
     , @StartDate + @T AS DateField
FROM #TaxVal
WHERE CustID = 18
    AND CompID = 101
ORDER BY DateField DESC

SET @T = @T + 1
END

到此:

;with cte as(
select cast('20150101' as date) as d
union all
select dateadd(dd, 1, d) as d from cte where d < '20150501'
)
INSERT INTO @Tab
SELECT CompID, d
FROM #TaxVal 
cross join cte
WHERE CustID = 18 AND CompID = 101
Option(maxrecursion 0)

这是recursive common table expression以获取范围内的所有日期。然后你做一个cross join并插入。请注意,插入时订单集没有任何意义。

答案 1 :(得分:0)

Giorgi的答案

;with cte as(
select cast('20150101' as date) as d
union all
select dateadd(dd, 1, d) as d from cte where d < '20150501'
)
INSERT INTO @Tab
SELECT CompID, d
FROM #TaxVal 
cross join cte
WHERE CustID = 18 AND CompID = 101

会起作用,但要小心递归CTE。如果日期范围很大,您将很快达到最大递归级别。通常,数字表的使用方式与HABO提到的非常相似。这只是一个包含单个列的表,只有一个整数,因此行可以是1,2,3,4,5等。然后,您可以加入Numbers表(外部应用适用于此)并使用数字dateadd获取增量日期。另请注意,您可能会遇到一个问题,即Numbers表格中没有足够的行包含您的日期范围。