Question

更新05/18/15

列上列有客户名称。如何在每个日期获得一个客户的百分比？例如

    CustomerName     Date
    Sam              04/29/15
    Joy              04/29/15
    Tom              04/29/15
    Sam              04/29/15
    Oly              04/29/15
    Joy              04/29/15
                     04/29/15
    Sam              04/29/15
                     04/29/15
    Sam              04/29/15
    Oly              04/29/15
    Sam              04/29/15
    Oly              04/30/15
    Joy              05/01/15

请注意，我的专栏有12条记录，其中2条是空白，但它们不会依赖于百分比，只有具有名称的记录。我想知道从总数中代表Sam的百分比（在这种情况下是10个记录，所以Sam％将是50）。

查询应返回

Date             Percentage
04/29/15            50
04/30/15            0
05/01/15            0

更新

我并不关心其他客户，所以我们将它们视为一体。只需要知道总列表中Sam的百分比是多少。

任何帮助都将非常感激。谢谢

Answer 1

您可以在子查询中计算每人+天的数字：

select  Date
,       CustomerName
,       100.0 * cnt / sum(cnt) over (partition by date)
from    (
        select  Date
        ,       CustomerName
        ,       count(*) cnt
        from    table1
        where   CustomerName <> ''
        group by
                Date
        ,       CustomerName
        ) t1

打印：

Date                    CustomerName 
----------------------- ------------ ---------------------------------------
2015-04-29 00:00:00.000 Joy          20.000000000000
2015-04-29 00:00:00.000 Oly          20.000000000000
2015-04-29 00:00:00.000 Sam          50.000000000000
2015-04-29 00:00:00.000 Tom          10.000000000000

(4 row(s) affected)

Answer 2

你会做这样的事情

SELECT (COUNT(*) * 100) / (SELECT COUNT(*) FROM Customer WHERE CustomerName <> '' AND Date = '04/29/15')
FROM Customer
WHERE CustomerName = 'Sam'
    AND Date = '04/29/15'

如果您希望每个日期获得count，则可以使用此

SELECT T.Date,((ISNULL(CustomerCount,0) * 100) / TotalCount)
FROM 
(
SELECT COUNT(*) as TotalCount,Date 
FROM Customer 
WHERE CustomerName <> ''
GROUP BY Date
)T
LEFT JOIN 
(
SELECT COUNT(*)
FROM Customer
WHERE CustomerName = 'Sam'
GROUP BY Date 
)C
ON T.Date = C.Date

Answer 3

你可以试试这个：

select name, date, (100.0 * count(*)) / 
    (select count(*) from table t2 
     where name is not null and name <> '' and t2.date = t1.date) 
from table t1
where name is not null and name <> ''
group by name, date

Answer 4

适用于所有用户

SELECT 
        (COUNT(*) * 100) / (SELECT COUNT(*) FROM Customer WHERE CustomerName <> '') as [percent],
         CustomerName
    FROM Customer group by CustomerName

用于特定用户

SELECT 
    (COUNT(*) * 100) / (SELECT COUNT(*) FROM Customer WHERE CustomerName <> '') as [percent],
     CustomerName
FROM Customer where CustomerName ='Sam'

如何根据列值获得百分比？

4 个答案: