Question

我有以下表格和数据：

CREATE TABLE customer_wer(
  id_customer NUMBER,
  name VARCHAR2(10),
  surname VARCHAR2(20),
  date_from DATE,
  date_to DATE NOT NULL,
  CONSTRAINT customer_wer_pk PRIMARY KEY (id_customer, data_from));

INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-JAN-00', '31-MAR-00');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-APR-00', '30-JUN-00');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '15-JUN-00', '30-SEP-00');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-OCT-00', '31-DEC-00');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-JAN-01', '31-MAR-01');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-APR-01', '30-JUN-01');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-JUL-01', '5-OCT-01');
INSERT INTO customer_wer VALUES (4, 'Karolina', 'Komuda', '01-OCT-01', '31-DEC-01');

我需要SELECT查询来查找日期重叠的记录。这意味着在上面的例子中，我应该在结果中有四个记录

number 
2
3
7
8

提前谢谢你。我正在使用Oracle DB。

Answer 1

之前的答案并不考虑t2完全在t1

范围内的情况

select * from t t1
join t t2 on (t1.datefrom > t2.datefrom and t1.datefrom < t2.dateto  )
          or (t1.dateto   > t2.datefrom and t1.dateto   < t2.dateto  )
          or (t1.dateto   > t2.dateto   and t1.datefrom < t2.datefrom)

Answer 2

试试这个：

select * from t t1
join t t2 on (t1.datefrom > t2.datefrom and t1.datefrom < t2.dateto)
          or (t1.dateto > t2.datefrom and t1.dateto < t2.dateto)

谢谢你这个例子。修改后它正在运行：

SELECT *
FROM customer_wer k
JOIN customer_wer w
ON k.id_customer = w.id_customer
WHERE (k.date_from > w.date_to AND k.date_from < w.date_to)
OR (k.date_to > w.date_from AND k.date_to < w.date_to);

Answer 3

如果每个开始日期小于或等于其他记录的结束日期，则它将在该范围内。

如果开始日期1小于结束日期2且开始日期2小于结束日期1。

 SELECT * 
 FROM t t1
    JOIN t t2 ON (t1.datefrom <= t2.dateto)
              AND (t2.datefrom <= t1.dateto)

Answer 4

类似于@Ben的答案...但检查重叠==天以及检查身份以确保它是唯一的。

select * from seasons t1
join seasons t2 on (t1.season_open  >= t2.season_open  and t1.season_open  <= t2.season_close and t1.id != t2.id)
                or (t1.season_close >= t2.season_open  and t1.season_close <= t2.season_close and t1.id != t2.id)
                or (t1.season_close >= t2.season_close and t1.season_open  <= t2.season_open  and t1.id != t2.id)

Answer 5

在我有很多数据的情况下，通过这种方式获得了更好的性能：

select *
from (
select id_customer,
       name,
       surname,
       date_from,
       date_to,
       lead(id_customer) over (partition by id_customer order by date_from) id_customer1,
       lead(name)        over (partition by id_customer order by date_from) name1,
       lead(surname)     over (partition by id_customer order by date_from) surname1,
       lead(date_from)   over (partition by id_customer order by date_from) date_from1,
       lead(date_to)     over (partition by id_customer order by date_from) date_to1
 from customer_wer)
where date_from1 <= date_to

在SQL中查找具有重叠日期范围的记录

5 个答案: