Question

我有一些数据表，我想从URL

中获取param id 194

admin/customer-management/updater/id/194

我的源AJAX：

"sAjaxSource": "/<?= Zend_Registry::get('Zend_Locale')->getLanguage(); ?>/admin/CustomerManagement/getlistcontactsajax/idCustomer/" + $(this).attr('value');

我执行此操作+ $(this).attr('value');但它不起作用。

Answer 1

可见，您使用PHP（使用Zend）编写js代码您可以使用以下命令恢复控制器中的ID：

$id = $this->getRequest()->getParam('id');

所以你可以用它编写你的js代码（可能在视图中传递变量）：

"sAjaxSource": "/<?=Zend_Registry::get('Zend_Locale')->getLanguage();?>/admin/CustomerManagement/getlistcontactsajax/idCustomer/<?= $id?>",

Answer 2

如果你有url变量，你可以使用正则表达式url.match(/\d+$/)来获取它

Answer 3

你可以这样做：

PortfolioCollectionDataContext context = null;
        context = DataContext;
        var Logins = from bkg in context.EnquiryBookings
                 join log in context.Logins
                 on log.LoginID equals bkg.LoginID
                 && bkg.Paid == true
                  join enq in context.Enquiries
                     on enq.EnquiryID equals bkg.EnquiryID
                  join estb in context.Establishments
                     on enq.EstablishmentID == estb.EstablishmentID
                  select new
                     {
                   str = "[Name: " + log.LastName + " " + log.FirstName + " - Country: " + log.CountryOfResidence + " - Phone: " 
                       + log.TelephoneNumber + " - Email: " + log.EmailAddress + " - Booked From: " 
                       + estb.CompanyName + " - Spent: " + bkg.TotalPrice.ToString() + "]"
                     };

        string output = string.Join(", ", Logins.ToList());

        return output;

或

parseInt(location.href.split("/").pop())

如何在JavaScript中的URL中传递参数

3 个答案: