Question

if class_number == 0:
    #This will create and open a new text file under the name
    #of the class_tag variable.
    file = open("Class 0" + ".txt", "a")
    #This will write down the user's name and their score
    file.write(str(name) + " scored " + str(score))
    #This will create a new line for each user
    file.write("\n")
    #This will close the file.
    file.close()

import collections

def new3ElementDeque():
   return collections.deque([], 3)

nameTop3 = collections.defaultdict(new3ElementDeque)

with open("Class 0.txt") as f:
    for line in f:
        user, score = line.split(':')
        nameTop3[name].append(score)

我试图让程序只保存用户的最后三个分数，而不是将所有分数保存到文本文件中。

现在看起来像这样：

student scored 3
student scored 8
student scored 0
student scored 4
student scored 10
student scored 3
student scored 0
student scored 4

我希望它是这样的：

student scored 3
student scored 0
student scored 4

但是，IDLE shell声明：

    name, score = line.split(':')
ValueError: need more than 1 value to unpack

如何让程序存储用户的最后三个分数并将其保存到文本文件？

输入的名称是：

name = input("What is your name? ")

Answer 1

没有＆＃39;：＆＃39;在line中，所以当它尝试将其拆分为＆＃39;：＆＃39;时，结果只有一个元素而您无法分配用户和分数，因为只有一个元素。

如果您文件中的所有行都是＆＃39;等等x＆＃39;，您可以将行user, score = line.split(':')替换为user, score = line.split(' scored ')

with open("Class 0.txt") as f:
    for line in f:
        user, score = line.split(' scored ')
        nameTop3[user].append(score)

程序不会让我只存储用户的最后三个分数

1 个答案: