Question

我试图执行一个选择插入，我需要使用序列和一个不同的子句。

我知道我们不能使用不同的序列，所以我在FROM中嵌套了一个子查询，如下所示：

INSERT INTO  SchemaName.XXSON_ST_B2B_CTR_PRICING
(SEQ_NO,SEEB_KEY,MESSAGE_ID,MESSAGE_TYPE,CREATE_DTIME,CHANGE_DTIME,STATUS)
   SELECT
          XXSON.XXSON_B2B_CTR_PRICING_SEQ.NEXTVAL   AS SEQ_NO,
         'SESS_NO'          AS SEEB_KEY,
          srp.ITEM          AS MESSAGE_ID,
         'MESSAGE_TYPE'     AS MESSAGE_TYPE,
          sysdate           AS CREATE_DTIME,
          sysdate           AS CHANGE_DTIME,
          'I'               AS STATUS
   FROM 
     (SELECT distinct srp.ITEM
      FROM  SchemaName.NB_PRICELIST_CTRL pctrl,
            SchemaName.NB_PRICELIST_SRP srp
      WHERE STATUS = 'W'
      AND SOURCE_TABLE = 'NB_PRICELIST_SRP');

然而，有了这个，我无法将srp.ITEM作为MESSAGE_ID插入，因为我有一个无效的标识符（ ORA-00904 ），这里不足为奇。有没有解决方法，所以我可以正确插入？

Answer 1

要摆脱alias，您必须将derived table分配给FROM，作为存储在内存中的普通表。在块内分配的INSERT INTO SchemaName.XXSON_ST_B2B_CTR_PRICING (SEQ_NO,SEEB_KEY,MESSAGE_ID,MESSAGE_TYPE,CREATE_DTIME,CHANGE_DTIME,STATUS) SELECT XXSON.XXSON_B2B_CTR_PRICING_SEQ.NEXTVAL AS SEQ_NO, 'SESS_NO' AS SEEB_KEY, alias.ITEM AS MESSAGE_ID, 'MESSAGE_TYPE' AS MESSAGE_TYPE, sysdate AS CREATE_DTIME, sysdate AS CHANGE_DTIME, 'I' AS STATUS FROM (SELECT distinct srp.ITEM FROM SchemaName.NB_PRICELIST_CTRL pctrl, SchemaName.NB_PRICELIST_SRP srp WHERE STATUS = 'W' AND SOURCE_TABLE = 'NB_PRICELIST_SRP') alias;子句中的别名在外部不可见。

my $key = (keys %hash)[0]

Answer 2

请尝试以下查询，这可能会对您有所帮助。

INSERT INTO  SchemaName.XXSON_ST_B2B_CTR_PRICING
(SEQ_NO,SEEB_KEY,MESSAGE_ID,MESSAGE_TYPE,CREATE_DTIME,CHANGE_DTIME,STATUS)
   SELECT
          XXSON.XXSON_B2B_CTR_PRICING_SEQ.NEXTVAL   AS SEQ_NO,
         'SESS_NO'          AS SEEB_KEY,
          (SELECT distinct srp.ITEM FROM  SchemaName.NB_PRICELIST_CTRL pctrl, SchemaName.NB_PRICELIST_SRP srp WHERE STATUS = 'W' AND SOURCE_TABLE = 'NB_PRICELIST_SRP') AS MESSAGE_ID,
         'MESSAGE_TYPE'     AS MESSAGE_TYPE,
          sysdate           AS CREATE_DTIME,
          sysdate           AS CHANGE_DTIME,
          'I'               AS STATUS;

问候。

Answer 3

您提供的错误消息处理丢失或无效的列。我相信错误消息的具体问题是

中的srp别名

srp.item as Message_ID

因为您没有在括号中对2个表的组合进行别名（您在内部对各个表进行别名，但这不会执行）。一个简单的解决方法是删除'srp'。从顶部陈述中“项目”的前面开始。

INSERT INTO  SchemaName.XXSON_ST_B2B_CTR_PRICING
(SEQ_NO,SEEB_KEY,MESSAGE_ID,MESSAGE_TYPE,CREATE_DTIME,CHANGE_DTIME,STATUS)
   SELECT
          XXSON.XXSON_B2B_CTR_PRICING_SEQ.NEXTVAL   AS SEQ_NO,
         'SESS_NO'          AS SEEB_KEY,
          ITEM          AS MESSAGE_ID,
         'MESSAGE_TYPE'     AS MESSAGE_TYPE,
          sysdate           AS CREATE_DTIME,
          sysdate           AS CHANGE_DTIME,
          'I'               AS STATUS
   FROM 
     (SELECT distinct srp.ITEM
      FROM SchemaName.NB_PRICELIST_CTRL pctrl,
        SchemaName.NB_PRICELIST_SRP srp
      WHERE STATUS = 'W'
      AND SOURCE_TABLE = 'NB_PRICELIST_SRP')

另外，我不太了解包含pctrl。

选择带有序列和不同的插入

3 个答案: